What is the molecular mass of baking soda, NaHCO3? (specify units) b) how many grams of oxygen are in 0.25 mol of baking soda? c) how many hydrogen atoms are present in 0.25 mol of baking soda? Please write out all the steps
The Correct Answer and Explanation is:
Let’s break it down step by step:
a) Molecular Mass of Baking Soda (NaHCO₃)
First, to find the molecular mass of NaHCO₃ (baking soda), we add up the atomic masses of each element in the compound. Here are the atomic masses of each element:
- Sodium (Na): 22.99 g/mol
- Hydrogen (H): 1.008 g/mol
- Carbon (C): 12.01 g/mol
- Oxygen (O): 16.00 g/mol (and there are three oxygen atoms)
Now, calculate the total molecular mass:
- Sodium: 1 × 22.99 g/mol = 22.99 g/mol
- Hydrogen: 1 × 1.008 g/mol = 1.008 g/mol
- Carbon: 1 × 12.01 g/mol = 12.01 g/mol
- Oxygen: 3 × 16.00 g/mol = 48.00 g/mol
So, the molecular mass of NaHCO₃ is: 22.99+1.008+12.01+48.00=84.008 g/mol22.99 + 1.008 + 12.01 + 48.00 = 84.008 \, \text{g/mol}22.99+1.008+12.01+48.00=84.008g/mol
Thus, the molecular mass of NaHCO₃ is 84.01 g/mol (rounded to 2 decimal places).
b) Grams of Oxygen in 0.25 mol of Baking Soda
To find how many grams of oxygen are in 0.25 mol of NaHCO₃, we use the molecular mass of oxygen in NaHCO₃.
From the formula, there are 3 oxygen atoms per molecule of NaHCO₃. The molar mass of oxygen in NaHCO₃ is: 3×16.00 g/mol=48.00 g/mol3 \times 16.00 \, \text{g/mol} = 48.00 \, \text{g/mol}3×16.00g/mol=48.00g/mol
Now, calculate how many grams of oxygen are in 0.25 mol of NaHCO₃: Grams of oxygen=0.25 mol×48.00 g/mol=12.00 grams of oxygen\text{Grams of oxygen} = 0.25 \, \text{mol} \times 48.00 \, \text{g/mol} = 12.00 \, \text{grams of oxygen}Grams of oxygen=0.25mol×48.00g/mol=12.00grams of oxygen
Thus, there are 12.00 grams of oxygen in 0.25 mol of baking soda.
c) Number of Hydrogen Atoms in 0.25 mol of Baking Soda
Next, we need to find how many hydrogen atoms are present in 0.25 mol of NaHCO₃.
From the chemical formula, NaHCO₃ contains 1 hydrogen atom per molecule. The number of molecules in 1 mole is Avogadro’s number, which is 6.022×10236.022 \times 10^{23}6.022×1023 molecules per mole. Therefore, in 0.25 mol of NaHCO₃, there are: 0.25 mol×6.022×1023 atoms/mol=1.5055×1023 hydrogen atoms0.25 \, \text{mol} \times 6.022 \times 10^{23} \, \text{atoms/mol} = 1.5055 \times 10^{23} \, \text{hydrogen atoms}0.25mol×6.022×1023atoms/mol=1.5055×1023hydrogen atoms
Thus, there are 1.5055 × 10²³ hydrogen atoms in 0.25 mol of baking soda.
Summary:
- a) Molecular mass of NaHCO₃: 84.01 g/mol
- b) Grams of oxygen in 0.25 mol of NaHCO₃: 12.00 g
- c) Number of hydrogen atoms in 0.25 mol of NaHCO₃: 1.5055 × 10²³ atoms
