How many Te atoms are in 3.03 g of TeO2

How many Te atoms are in 3.03 g of TeO2? Molar mass Te = 127.6 g/mol; Molar mass O = 16.00 g/mol. Enter only a numerical answer, do not enter units. To enter answers such as 3.2 x 10^12, enter as 3.2E12. All other formats will be marked incorrect by the system.

The Correct Answer and Explanation is:

To determine how many Te atoms are in 3.03 g of TeO2, follow these steps:

1. Calculate the molar mass of TeO2:
   • Molar mass of Te = 127.6 g/mol
   • Molar mass of O = 16.00 g/mol
   • TeO2 has one Te atom and two O atoms. So, the molar mass of TeO2 is:
   Molar mass of TeO2=127.6+(2×16.00)=127.6+32.00=159.6 g/mol\text{Molar mass of TeO2} = 127.6 + (2 \times 16.00) = 127.6 + 32.00 = 159.6 \, \text{g/mol}Molar mass of TeO2=127.6+(2×16.00)=127.6+32.00=159.6g/mol
2. Calculate the number of moles of TeO2 in 3.03 g:
   • Moles of TeO2 = Mass of TeO2Molar mass of TeO2\frac{\text{Mass of TeO2}}{\text{Molar mass of TeO2}}Molar mass of TeO2Mass of TeO2​
   Moles of TeO2=3.03159.6=0.01898 mol\text{Moles of TeO2} = \frac{3.03}{159.6} = 0.01898 \, \text{mol}Moles of TeO2=159.63.03​=0.01898mol
3. Calculate the number of moles of Te atoms:
   • Each mole of TeO2 contains 1 mole of Te atoms (because there is 1 Te atom per TeO2 molecule).
   Moles of Te=0.01898 mol\text{Moles of Te} = 0.01898 \, \text{mol}Moles of Te=0.01898mol
4. Calculate the number of Te atoms:
   • Avogadro’s number = 6.022×1023 atoms/mol6.022 \times 10^{23} \, \text{atoms/mol}6.022×1023atoms/mol
   Number of Te atoms=Moles of Te×6.022×1023\text{Number of Te atoms} = \text{Moles of Te} \times 6.022 \times 10^{23}Number of Te atoms=Moles of Te×6.022×1023 Number of Te atoms=0.01898×6.022×1023=1.14×1022\text{Number of Te atoms} = 0.01898 \times 6.022 \times 10^{23} = 1.14 \times 10^{22}Number of Te atoms=0.01898×6.022×1023=1.14×1022

Thus, the number of Te atoms in 3.03 g of TeO2 is 1.14E22.