What is the molar mass of Mn(ClO3)2

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What is the molar mass of Mn(ClO3)2? Show all work and explain your calculations.

The Correct Answer and Explanation is:

To calculate the molar mass of Mn(ClO₃)₂, we need to find the atomic masses of each element involved and then sum them up based on the number of atoms of each element in the compound.

Step-by-Step Calculation:

  1. Manganese (Mn):
    • The atomic mass of manganese (Mn) is 54.94 g/mol.
  2. Chlorine (Cl):
    • The atomic mass of chlorine (Cl) is 35.45 g/mol.
  3. Oxygen (O):
    • The atomic mass of oxygen (O) is 16.00 g/mol.

Now, let’s break down the compound Mn(ClO₃)₂:

  • There is 1 atom of Mn in the formula, so the mass contribution from Mn is: 1×54.94 g/mol=54.94 g/mol1 \times 54.94 \, \text{g/mol} = 54.94 \, \text{g/mol}1×54.94g/mol=54.94g/mol
  • There are 2 chlorine atoms (Cl), and each chlorine atom contributes 35.45 g/mol. So, the mass contribution from chlorine is: 2×35.45 g/mol=70.90 g/mol2 \times 35.45 \, \text{g/mol} = 70.90 \, \text{g/mol}2×35.45g/mol=70.90g/mol
  • There are 6 oxygen atoms (O) in total, because each of the two chlorate ions (ClO₃) has three oxygen atoms. The mass contribution from oxygen is: 6×16.00 g/mol=96.00 g/mol6 \times 16.00 \, \text{g/mol} = 96.00 \, \text{g/mol}6×16.00g/mol=96.00g/mol

Adding It All Together:

Now, let’s sum the masses of each element: 54.94 g/mol (Mn)+70.90 g/mol (Cl)+96.00 g/mol (O)=221.84 g/mol54.94 \, \text{g/mol} \, (\text{Mn}) + 70.90 \, \text{g/mol} \, (\text{Cl}) + 96.00 \, \text{g/mol} \, (\text{O}) = 221.84 \, \text{g/mol}54.94g/mol(Mn)+70.90g/mol(Cl)+96.00g/mol(O)=221.84g/mol

Final Answer:

The molar mass of Mn(ClO₃)₂ is 221.84 g/mol.

Explanation:

Molar mass is simply the sum of the atomic masses of the elements in a compound, weighted by how many atoms of each element are present in the chemical formula. By looking at the number of atoms of manganese, chlorine, and oxygen, we calculate the total mass of one mole of Mn(ClO₃)₂. This process is essential for stoichiometric calculations in chemistry, helping you convert between mass and moles when working with reactions or solutions.

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