write the balanced equation for the following reaction and verified type of reaction sodium hydroxide solution is treated with Acetic Acid to form Sodium Acetate at water with explain
The Correct Answer and Explanation is:
The reaction between sodium hydroxide (NaOH) and acetic acid (CH₃COOH) is a neutralization reaction. The balanced chemical equation for this reaction is:NaOH (aq)+CH₃COOH (aq)→CH₃COONa (aq)+H₂O (l)\text{NaOH (aq)} + \text{CH₃COOH (aq)} \rightarrow \text{CH₃COONa (aq)} + \text{H₂O (l)}NaOH (aq)+CH₃COOH (aq)→CH₃COONa (aq)+H₂O (l)
Explanation:
This is an example of an acid-base neutralization reaction. Here’s a breakdown of the components:
- Sodium Hydroxide (NaOH): This is a strong base that dissociates in water to produce hydroxide ions (OH⁻).
- Acetic Acid (CH₃COOH): This is a weak acid that dissociates to produce hydrogen ions (H⁺) in water.
In a neutralization reaction, the hydrogen ion (H⁺) from the acid combines with the hydroxide ion (OH⁻) from the base to form water (H₂O). The remaining parts of the acid and base (the acetate ion, CH₃COO⁻, and the sodium ion, Na⁺) combine to form sodium acetate (CH₃COONa), which is a salt.
Thus, the acid and the base neutralize each other, resulting in a salt and water as the products.
Type of Reaction:
This is an acid-base neutralization reaction because:
- The hydrogen ion (H⁺) from the acetic acid reacts with the hydroxide ion (OH⁻) from sodium hydroxide.
- It produces a neutral compound, water (H₂O), and a salt, sodium acetate (CH₃COONa).
Key Points:
- Acid: Acetic acid (CH₃COOH)
- Base: Sodium hydroxide (NaOH)
- Products: Water (H₂O) and Sodium acetate (CH₃COONa)
Neutralization reactions typically involve the reaction of an acid and a base to produce a salt and water, which is exactly what happens in this case.
