What is the molar mass of acetaminophen, C8H9NO2

What is the molar mass of acetaminophen, C8H9NO2? Show calculations.

The Correct Answer and Explanation is:

To calculate the molar mass of acetaminophen (C8H9NO2), we sum the molar masses of each element present in the compound, based on the number of atoms of each element.

Step 1: Identify the elements and their quantities

Acetaminophen has the molecular formula C8H9NO2. This means:

  • 8 carbon (C) atoms
  • 9 hydrogen (H) atoms
  • 1 nitrogen (N) atom
  • 2 oxygen (O) atoms

Step 2: Find the atomic masses

From the periodic table, the approximate atomic masses of the elements are:

  • Carbon (C): 12.01 g/mol
  • Hydrogen (H): 1.008 g/mol
  • Nitrogen (N): 14.01 g/mol
  • Oxygen (O): 16.00 g/mol

Step 3: Calculate the molar mass

Now, we calculate the molar mass by multiplying the atomic masses of each element by the number of atoms of that element in the formula:Molar mass of acetaminophen=(8×12.01)+(9×1.008)+(1×14.01)+(2×16.00)\text{Molar mass of acetaminophen} = (8 \times 12.01) + (9 \times 1.008) + (1 \times 14.01) + (2 \times 16.00)Molar mass of acetaminophen=(8×12.01)+(9×1.008)+(1×14.01)+(2×16.00)

Breaking it down:

  • 8×12.01=96.08 g/mol8 \times 12.01 = 96.08 \, \text{g/mol}8×12.01=96.08g/mol
  • 9×1.008=9.072 g/mol9 \times 1.008 = 9.072 \, \text{g/mol}9×1.008=9.072g/mol
  • 1×14.01=14.01 g/mol1 \times 14.01 = 14.01 \, \text{g/mol}1×14.01=14.01g/mol
  • 2×16.00=32.00 g/mol2 \times 16.00 = 32.00 \, \text{g/mol}2×16.00=32.00g/mol

Now, summing all these values:96.08+9.072+14.01+32.00=151.162 g/mol96.08 + 9.072 + 14.01 + 32.00 = 151.162 \, \text{g/mol}96.08+9.072+14.01+32.00=151.162g/mol

Step 4: Round the result

The molar mass of acetaminophen is approximately 151.16 g/mol.

Explanation

The molar mass is the sum of the masses of the atoms in one mole of the compound. Acetaminophen’s molar mass, as calculated above, tells us that one mole of acetaminophen weighs about 151.16 grams. This calculation is important because it allows chemists to determine how much of the compound is needed for a given amount of substance in moles, which is crucial for stoichiometric calculations in reactions.

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