3.0 ml of cyclopentadiene to grams to moles
The Correct Answer and Explanation is:
To convert 3.0 mL of cyclopentadiene (C₅H₆) to grams and then to moles, follow these steps:
Step 1: Convert the Volume of Cyclopentadiene to Mass
The density of cyclopentadiene is 0.802 g/mL at 20°C. This means that for every milliliter (mL) of cyclopentadiene, it weighs 0.802 grams.
Using this density, we can calculate the mass of 3.0 mL of cyclopentadiene: Mass=Volume×Density\text{Mass} = \text{Volume} \times \text{Density} Mass=Volume×Density Mass=3.0 mL×0.802 g/mL=2.406 g\text{Mass} = 3.0 \, \text{mL} \times 0.802 \, \text{g/mL} = 2.406 \, \text{g}Mass=3.0mL×0.802g/mL=2.406g
So, 3.0 mL of cyclopentadiene has a mass of 2.406 grams.
Step 2: Convert the Mass to Moles
To convert the mass of cyclopentadiene to moles, we need the molar mass of cyclopentadiene. The molecular formula of cyclopentadiene is C₅H₆. To find the molar mass: Molar Mass=(5×Atomic mass of C)+(6×Atomic mass of H)\text{Molar Mass} = (5 \times \text{Atomic mass of C}) + (6 \times \text{Atomic mass of H})Molar Mass=(5×Atomic mass of C)+(6×Atomic mass of H) Molar Mass=(5×12.01 g/mol)+(6×1.008 g/mol)=60.05 g/mol+6.048 g/mol=66.098 g/mol\text{Molar Mass} = (5 \times 12.01 \, \text{g/mol}) + (6 \times 1.008 \, \text{g/mol}) = 60.05 \, \text{g/mol} + 6.048 \, \text{g/mol} = 66.098 \, \text{g/mol}Molar Mass=(5×12.01g/mol)+(6×1.008g/mol)=60.05g/mol+6.048g/mol=66.098g/mol
Now, to convert the mass of cyclopentadiene to moles: Moles=MassMolar Mass=2.406 g66.098 g/mol=0.0364 mol\text{Moles} = \frac{\text{Mass}}{\text{Molar Mass}} = \frac{2.406 \, \text{g}}{66.098 \, \text{g/mol}} = 0.0364 \, \text{mol}Moles=Molar MassMass=66.098g/mol2.406g=0.0364mol
Final Answer:
- Mass: 3.0 mL of cyclopentadiene weighs 2.406 grams.
- Moles: 3.0 mL of cyclopentadiene is 0.0364 moles.
Explanation:
- The density of cyclopentadiene is used to convert volume to mass.
- The molar mass of cyclopentadiene is calculated using the atomic masses of carbon and hydrogen.
- Finally, the mass is divided by the molar mass to determine the number of moles.
