Calculate the molar mass of aluminum nitrate, Al(NO3)3. The answer should be rounded to the nearest whole number. Do not include units in your answer. Enter the answer. Check it.
The Correct Answer and Explanation is:
To calculate the molar mass of aluminum nitrate (Al(NO3)3), we need to add up the atomic masses of all the elements in the compound.
Step-by-step calculation:
- Aluminum (Al):
- The atomic mass of aluminum is approximately 27.0 g/mol.
- Nitrogen (N):
- Each nitrate ion (NO3-) contains 1 nitrogen atom.
- The atomic mass of nitrogen is approximately 14.0 g/mol.
- Since there are 3 nitrate ions in Al(NO3)3, we multiply the atomic mass of nitrogen by 3:
14.0 g/mol × 3 = 42.0 g/mol.
- Oxygen (O):
- Each nitrate ion (NO3-) contains 3 oxygen atoms.
- The atomic mass of oxygen is approximately 16.0 g/mol.
- Since there are 3 nitrate ions, the total number of oxygen atoms is 3 × 3 = 9.
- Therefore, the total mass from oxygen is:
16.0 g/mol × 9 = 144.0 g/mol.
Now, we sum all the contributions:
- Aluminum (Al): 27.0 g/mol
- Nitrogen (N): 42.0 g/mol
- Oxygen (O): 144.0 g/mol
Total molar mass of Al(NO3)3 = 27.0 g/mol + 42.0 g/mol + 144.0 g/mol = 213.0 g/mol.
Answer: 213
