Exams & Certification

Exams & Certification

what mass of sodium hydroxide has the same number of oxygen atoms as 130g of barium dihydrogen phosphate

what mass of sodium hydroxide has the same number of oxygen atoms as 130g of barium dihydrogen phosphate The Correct Answer and Explanation is: Step 1: Determine the number of oxygen atoms in 130 g of Ba(H₂PO₄)₂ Step 2: Determine the mass of NaOH that contains 3.139 mol of oxygen atoms Final Answer: 125.54 grams

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Complete and balance the following acid/base reactions. Include solubility state as well.

Complete and balance the following acid/base reactions. Include solubility state as well. Ba(OH)2(aq) + H3PO4(aq) ? NH3(aq) + H2SO4(aq) The Correct Answer and Explanation is: 1. Ba(OH)₂(aq) + H₃PO₄(aq) → ? Step 1: Identify the acid and base Step 2: Write the products of neutralization Acid + Base → Salt + WaterBa(OH)₂ provides 2 OH⁻,

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Creating a method object

Creating a method object. Define the method object inc_num_kids() for PersonInfo. inc_num_kids increments the member data num_kids. Sample output for the given program with one call to inc_num_kids(): Kids: 0 New baby, kids now: 1 1 class PersonInfo: 2 3 def init(self): 4 self.num_kids = 0 5 6 # FIXME: Write inc_num_kids(self) 7 8 person1

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An object is moving east and its velocity changes from 65 m/s to 25 m/s in 10 seconds

An object is moving east and its velocity changes from 65 m/s to 25 m/s in 10 seconds The Correct Answer and Explanation is: To calculate the acceleration of an object, use the formula:Acceleration (a)=Final velocity (v)−Initial velocity (u)Time (t)\text{Acceleration (a)} = \frac{\text{Final velocity (v)} – \text{Initial velocity (u)}}{\text{Time (t)}}Acceleration (a)=Time (t)Final velocity (v)−Initial velocity (u)​ Given:Initial velocity, u=65 m/su = 65 \, \text{m/s}u=65m/sFinal velocity, v=25 m/sv = 25

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If the velocity of an object changes from 65 m/s to 98 M/s during a time interval of 12 s what is the acceleration of the object

If the velocity of an object changes from 65 m/s to 98 M/s during a time interval of 12 s what is the acceleration of the object The Correct Answer and Explanation is: Answer: To find the acceleration, we use the formula:Acceleration=Final velocity−Initial velocityTime\text{Acceleration} = \frac{{\text{Final velocity} – \text{Initial velocity}}}{{\text{Time}}}Acceleration=TimeFinal velocity−Initial velocity​ Given: a=98 m/s−65 m/s12 s=33 m/s12 s=2.75 m/s2a = \frac{{98\, \text{m/s} – 65\,

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