Acetone + 2 benzaldehyde \rightarrow dibenzalacetone Molecular Weight: 234.2980
Acetone + 2 benzaldehyde \rightarrow dibenzalacetone Molecular Weight: 234.2980 The Correct Answer and Explanation is: Balanced Chemical Equation: acetone+2 benzaldehyde→dibenzalacetone+water\text{acetone} + 2 \ \text{benzaldehyde} \rightarrow \text{dibenzalacetone} + \text{water}acetone+2 benzaldehyde→dibenzalacetone+water Given: Step 1: Convert Volume of Benzaldehyde to Mass mass=volume×density=8.00 mL×1.044 g/mL=8.352 g\text{mass} = \text{volume} \times \text{density} = 8.00 \ \text{mL} \times 1.044 \ \text{g/mL} = 8.352 \ \text{g}mass=volume×density=8.00 mL×1.044 g/mL=8.352 g Step 2: […]
Acetone + 2 benzaldehyde \rightarrow dibenzalacetone Molecular Weight: 234.2980 Read More »