Why doesn’t sin^-1(sin(3pi/4)) not equal 3pi/4 when y=sin x and y+sin^-1x are inverses
Why doesn’t sin^-1(sin(3pi/4)) not equal 3pi/4 when y=sin x and y+sin^-1x are inverses? Is it because its an odd function? The Correct Answer and Explanation is : The reason why (\sin^{-1}(\sin(\frac{3\pi}{4}))) does not equal (\frac{3\pi}{4}) is not because the sine function is odd, but because the range of the inverse sine function, (\sin^{-1}), is limited […]
Why doesn’t sin^-1(sin(3pi/4)) not equal 3pi/4 when y=sin x and y+sin^-1x are inverses Read More »