{"id":112505,"date":"2023-08-15T18:00:36","date_gmt":"2023-08-15T18:00:36","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=112505"},"modified":"2023-08-15T18:00:39","modified_gmt":"2023-08-15T18:00:39","slug":"chem-120-final-exam-chem120-week-8-final-exam-latest-actual-exam-2023-2024-questions-and-correct-detailed-answersagrade","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2023\/08\/15\/chem-120-final-exam-chem120-week-8-final-exam-latest-actual-exam-2023-2024-questions-and-correct-detailed-answersagrade\/","title":{"rendered":"CHEM 120 FINAL EXAM \/CHEM120 WEEK 8 FINAL EXAM LATEST ACTUAL EXAM 2023-2024 QUESTIONS AND CORRECT DETAILED ANSWERS|AGRADE"},"content":{"rendered":"\n<p>lOMoAR cPSD|19500986<br>CHEM 120 FINAL EXAM \/CHEM120 WEEK 8 FINAL EXAM<br>LATEST ACTUAL EXAM 2023-2024 QUESTIONS AND<br>CORRECT DETAILED ANSWERS|AGRADE<br>The heat of fusion of water at 0 C is 334 Joules\/gram. How many joules of energy wouldneed to<br>be removed from 2 moles of water at 0 C to convert it into ice at 0 C? Ans: 12.0 kJ.<br>Question 26. Concentrated hydrochloric acid has a density of 1.19 g\/mL and a concentration of<br>38% by mass. What is the molarity of acid in the solution?<br>A. 1.041 M<br>B. 12.4 M<br>C. 17 M<br>D. 0.23 M<br>E None of the above.<br>Question . What is the molality of a 2.30 M solution of sodium nitrate whose density is 1.08<br>g\/mL?<br>A. 3.2 m<br>B. 2.6 m<br>C. 2.3 m<br>D. 0.0023 m<br>E 0.0026 m<br>Question . What is the vapor pressure at 50 C of a solution consisting of 70.7 g hexane and<br>0.100 moles of a nonvolatile solute? The vapor pressure of pure hexane (C6H14) at 50 C is 399<br>mm Hg.<br>A. 0.057 atm<br>B. 0.525 atm<br>C. 546 atm<br>D. 355 atm<br>E. 0.468 atm<br>Question . How many moles of CO2 are in 2.8 liters of sparking water that was prepared at a<br>pressure of 4.2 atm (25 C). The density of the solution is 1.20 g\/mL.<br>A. 0.486 moles<br>B. 0.405 moles<br>C. 0.400 moles<br>D. 0.338 moles<br>E. 0.145 moles<br>Question. What mass of glucose (C6H12O6), a molecule that does not break into particles,<br>must be dissolved in 750.0 g water to give a solution with a boiling point of 101.50 C?<br>A. 26,760 g<br>B. 395 g<br>C. 26.7 g<br>D. 2.9 g<br>E. 2.2 g<\/p>\n\n\n\n<p>lOMoAR cPSD|19500986<br>Question . A 550 mL aqueous solution containing 600 mg of bovine insulin (a protein, not<br>ionized) has an osmotic pressure of 6.7 mm Hg at 37 C. What is the molecular weight of insulin?<\/p>\n\n\n\n<p>lOMoAR cPSD|19500986<br>A. 4.1 g\/mol<br>B. 600 g\/mol<br>C. 3140 g\/mol<br>D. 23,000 g\/mol<br>E. 3.0&#215;106<br>g\/mol<br>What mass of glycerin (C3H8O3), a molecule that does not break into particles, must be dissolved<br>in 200.0 g water to give a solution with a freezing point of -2.50 C?<br>A. 0.269 g<br>B. 1.34 g<br>C. 13.7 g<br>D. 24.7 g<br>E. 123.6 g<br>Concentrated nitric acid has a density of 1.42 g\/mL and a concentration of 16 M. What is the<br>percent acid by weight in the solution?<br>A. 18%<br>B. 38%<br>C. 79%<br>D. 99%<br>E None of the above.<br>Question 12. A solution of phosphoric acid was made by dissolving 10.0 g H3PO4 in 100.0 mL<br>water. The resulting volume was 104 mL. Calculate the mole fraction of phosphoric acid in the<br>solution. Water has a density of 0.997 g\/mL.<br>A. 0.0181<br>B. 0.981 moles\/L<br>C. 0.0148<br>D. 1.02 moles\/Kg<br>E. 0.1020<br>Question 13. What is the vapor pressure at 60 C of a solution consisting of 60.5 g pentane and<br>0.200 moles of a nonvolatile solute? The vapor pressure of pure pentane (C5H12) at 60 C is 457<br>mm Hg.<br>A. 0.116 atm<br>B. 0.525 atm<br>C. 146 atm<br>D. 369 atm<br>E. 0.486 atm<br>Question 14. Estimate the boiling point of a 0.35 m aqueous solution of CaCl2.<br>A. 100.54 C<br>B. 99.46 C<br>C. 100.18 C<br>D 99.82 C<br>E 100.36 C<br><\/p>\n","protected":false},"excerpt":{"rendered":"<p>lOMoAR cPSD|19500986CHEM 120 FINAL EXAM \/CHEM120 WEEK 8 FINAL EXAMLATEST ACTUAL EXAM 2023-2024 QUESTIONS ANDCORRECT DETAILED ANSWERS|AGRADEThe heat of fusion of water at 0 C is 334 Joules\/gram. How many joules of energy wouldneed tobe removed from 2 moles of water at 0 C to convert it into ice at 0 C? Ans: 12.0 kJ.Question [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-112505","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/112505","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=112505"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/112505\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=112505"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=112505"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=112505"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}