A nurse is preparing to administer dexamethasone 0.5 mg\/kg\/day IM to divide equally every 6 hr to a client who weighs 132 lb. Available is dexamethasone 4 mg\/mL. How many mL should the nurse administer per dose? (Round the answer to the nearest tenth. Use a leading zero if it applies. Do not use a trailing zero.)<\/p>\n\n\n\n
The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n To determine the amount of dexamethasone the nurse should administer per dose, follow these steps:<\/p>\n\n\n\n Summary:<\/strong> The nurse should administer 1.9 mL<\/strong> of dexamethasone per dose.<\/p>\n","protected":false},"excerpt":{"rendered":" A nurse is preparing to administer dexamethasone 0.5 mg\/kg\/day IM to divide equally every 6 hr to a client who weighs 132 lb. Available is dexamethasone 4 mg\/mL. How many mL should the nurse administer per dose? (Round the answer to the nearest tenth. Use a leading zero if it applies. Do not use a […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-135010","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/135010","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=135010"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/135010\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=135010"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=135010"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=135010"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}\n
The client’s weight is 132 lb. To convert pounds to kilograms, use the conversion factor (1 \\text{ lb} = 0.4536 \\text{ kg}):
[
\\text{Weight (kg)} = 132 \\text{ lb} \\times 0.4536 \\text{ kg\/lb} = 59.87 \\text{ kg} \\approx 59.9 \\text{ kg}
]<\/li>\n\n\n\n
The order is for 0.5 mg\/kg\/day. Thus, calculate the total daily dose as follows:
[
\\text{Total daily dose (mg)} = 0.5 \\text{ mg\/kg\/day} \\times 59.9 \\text{ kg} = 29.95 \\text{ mg} \\approx 30.0 \\text{ mg}
]<\/li>\n\n\n\n
The daily dose needs to be divided into doses administered every 6 hours. There are 24 hours in a day, so:
[
\\text{Number of doses per day} = \\frac{24 \\text{ hours}}{6 \\text{ hours\/dose}} = 4 \\text{ doses\/day}
]
Therefore, the dose per administration is:
[
\\text{Dose per administration (mg)} = \\frac{30.0 \\text{ mg}}{4} = 7.5 \\text{ mg}
]<\/li>\n\n\n\n
The available concentration is 4 mg\/mL. To find out how many mL are needed for each dose:
[
\\text{Volume to administer (mL)} = \\frac{\\text{Dose per administration (mg)}}{\\text{Concentration (mg\/mL)}} = \\frac{7.5 \\text{ mg}}{4 \\text{ mg\/mL}} = 1.875 \\text{ mL}
]
Rounding this to the nearest tenth gives:
[
1.9 \\text{ mL}
]<\/li>\n<\/ol>\n\n\n\n