{"id":136052,"date":"2024-09-09T20:43:32","date_gmt":"2024-09-09T20:43:32","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=136052"},"modified":"2024-09-09T20:43:34","modified_gmt":"2024-09-09T20:43:34","slug":"a-nurse-is-preparing-to-administer-foscarnet-60-mg-kg-via-intermittent-iv-bolus-to-a-client-who-weighs-126-lb","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2024\/09\/09\/a-nurse-is-preparing-to-administer-foscarnet-60-mg-kg-via-intermittent-iv-bolus-to-a-client-who-weighs-126-lb\/","title":{"rendered":"A nurse is preparing to administer foscarnet 60 mg\/kg via intermittent IV bolus to a client who weighs 126 lb"},"content":{"rendered":"\n<p>A nurse is preparing to administer foscarnet 60 mg\/kg via intermittent IV bolus to a client who weighs 126 lb. Available is foscarnet 6,000 mg in 500 mL of 0.9% sodium chloride solution. How many ml should the nurse administer? (Round the answer to the nearest whole number. Use a leading zero if it applies. Do not use a trailing zero.)<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To solve this dosage calculation problem, follow these steps:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Convert the client\u2019s weight from pounds to kilograms.<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The formula for converting pounds to kilograms is: Weight\u00a0in\u00a0kilograms=Weight\u00a0in\u00a0pounds2.2\\text{Weight in kilograms} = \\frac{\\text{Weight in pounds}}{2.2}Weight\u00a0in\u00a0kilograms=2.2Weight\u00a0in\u00a0pounds\u200b So, the client&#8217;s weight in kilograms is: 126\u00a0lb2.2=57.27\u00a0kg\u224857.3\u00a0kg\\frac{126 \\text{ lb}}{2.2} = 57.27 \\text{ kg} \\approx 57.3 \\text{ kg}2.2126\u00a0lb\u200b=57.27\u00a0kg\u224857.3\u00a0kg<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Determine the prescribed dose in milligrams.<\/h3>\n\n\n\n<p>The order is for <strong>60 mg\/kg<\/strong>, and the client weighs <strong>57.3 kg<\/strong>. To calculate the total dose of foscarnet:Dose=60&nbsp;mg\/kg\u00d757.3&nbsp;kg=3,438&nbsp;mg\\text{Dose} = 60 \\text{ mg\/kg} \\times 57.3 \\text{ kg} = 3,438 \\text{ mg}Dose=60&nbsp;mg\/kg\u00d757.3&nbsp;kg=3,438&nbsp;mg<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Determine the concentration of the available solution.<\/h3>\n\n\n\n<p>You have <strong>6,000 mg<\/strong> of foscarnet in <strong>500 mL<\/strong> of 0.9% sodium chloride solution. To find the concentration (mg\/mL):Concentration=6,000&nbsp;mg500&nbsp;mL=12&nbsp;mg\/mL\\text{Concentration} = \\frac{6,000 \\text{ mg}}{500 \\text{ mL}} = 12 \\text{ mg\/mL}Concentration=500&nbsp;mL6,000&nbsp;mg\u200b=12&nbsp;mg\/mL<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 4: Calculate the volume of the solution to be administered.<\/h3>\n\n\n\n<p>Using the concentration of the available solution, we can calculate the volume to be administered:Volume&nbsp;(mL)=Prescribed&nbsp;dose&nbsp;(mg)Concentration&nbsp;(mg\/mL)\\text{Volume (mL)} = \\frac{\\text{Prescribed dose (mg)}}{\\text{Concentration (mg\/mL)}}Volume&nbsp;(mL)=Concentration&nbsp;(mg\/mL)Prescribed&nbsp;dose&nbsp;(mg)\u200b Volume&nbsp;(mL)=3,438&nbsp;mg12&nbsp;mg\/mL=286.5&nbsp;mL\u2248287&nbsp;mL\\text{Volume (mL)} = \\frac{3,438 \\text{ mg}}{12 \\text{ mg\/mL}} = 286.5 \\text{ mL} \\approx 287 \\text{ mL}Volume&nbsp;(mL)=12&nbsp;mg\/mL3,438&nbsp;mg\u200b=286.5&nbsp;mL\u2248287&nbsp;mL<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Final Answer:<\/h3>\n\n\n\n<p>The nurse should administer <strong>287 mL<\/strong> of the foscarnet solution.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>In this problem, the nurse must administer foscarnet based on the client\u2019s weight. First, the client&#8217;s weight is converted from pounds to kilograms to match the dosage calculation in mg\/kg. The prescribed dose is then calculated by multiplying the dose per kilogram by the client\u2019s weight in kilograms. Once the total dose in milligrams is determined, the next step is to determine how many milliliters of the available solution are needed to provide this dose. The available solution concentration (12 mg\/mL) is used to divide the total prescribed dose, giving the final volume in milliliters. This ensures the nurse administers the correct amount of medication safely. The rounding rules ensure the result is in a practical format for administration.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>A nurse is preparing to administer foscarnet 60 mg\/kg via intermittent IV bolus to a client who weighs 126 lb. Available is foscarnet 6,000 mg in 500 mL of 0.9% sodium chloride solution. How many ml should the nurse administer? (Round the answer to the nearest whole number. Use a leading zero if it applies. [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-136052","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/136052","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=136052"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/136052\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=136052"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=136052"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=136052"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}