{"id":136218,"date":"2024-09-10T10:19:45","date_gmt":"2024-09-10T10:19:45","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=136218"},"modified":"2024-09-10T10:19:47","modified_gmt":"2024-09-10T10:19:47","slug":"a-patient-is-receiving-an-iv-of-esmolol-2-5-grams-in-250-ml-d5w-dextrose-5-in-water-infusing-at-200-micrograms-kilogram-minute","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2024\/09\/10\/a-patient-is-receiving-an-iv-of-esmolol-2-5-grams-in-250-ml-d5w-dextrose-5-in-water-infusing-at-200-micrograms-kilogram-minute\/","title":{"rendered":"A patient is receiving an IV of esmolol 2.5 grams in 250 mL D5W (dextrose 5% in water) infusing at 200 micrograms\/kilogram\/minute"},"content":{"rendered":"\n<p>A patient is receiving an IV of esmolol 2.5 grams in 250 mL D5W (dextrose 5% in water) infusing at 200 micrograms\/kilogram\/minute. The patient weighs 110 lb. What rate (in mL\/hr) should the nurse program into the IV pump to deliver this dose?<\/p>\n\n\n\n<p>A.<br>45 mL\/hr<\/p>\n\n\n\n<p>B.<br>60 mL\/hr<\/p>\n\n\n\n<p>C.<br>75 mL\/hr<\/p>\n\n\n\n<p>D.<br>90 mL\/hr<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To determine the correct IV infusion rate for the esmolol infusion, we need to follow these steps:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Convert the patient\u2019s weight from pounds to kilograms:<\/strong>The patient weighs 110 pounds. To convert this to kilograms:Weight\u00a0(kg)=Weight\u00a0(lb)\u00d71\u00a0kg2.2\u00a0lb\\text{Weight (kg)} = \\text{Weight (lb)} \\times \\frac{1 \\text{ kg}}{2.2 \\text{ lb}}Weight\u00a0(kg)=Weight\u00a0(lb)\u00d72.2\u00a0lb1\u00a0kg\u200b Weight\u00a0(kg)=110\u00a0lb\u00d71\u00a0kg2.2\u00a0lb=50\u00a0kg\\text{Weight (kg)} = 110 \\text{ lb} \\times \\frac{1 \\text{ kg}}{2.2 \\text{ lb}} = 50 \\text{ kg}Weight\u00a0(kg)=110\u00a0lb\u00d72.2\u00a0lb1\u00a0kg\u200b=50\u00a0kg<\/li>\n\n\n\n<li><strong>Calculate the total dose required per minute:<\/strong>The esmolol infusion rate is 200 micrograms per kilogram per minute.Dose\u00a0(micrograms\/min)=Weight\u00a0(kg)\u00d7Rate\u00a0(micrograms\/kg\/min)\\text{Dose (micrograms\/min)} = \\text{Weight (kg)} \\times \\text{Rate (micrograms\/kg\/min)}Dose\u00a0(micrograms\/min)=Weight\u00a0(kg)\u00d7Rate\u00a0(micrograms\/kg\/min) Dose\u00a0(micrograms\/min)=50\u00a0kg\u00d7200\u00a0micrograms\/kg\/min=10,000\u00a0micrograms\/min\\text{Dose (micrograms\/min)} = 50 \\text{ kg} \\times 200 \\text{ micrograms\/kg\/min} = 10,000 \\text{ micrograms\/min}Dose\u00a0(micrograms\/min)=50\u00a0kg\u00d7200\u00a0micrograms\/kg\/min=10,000\u00a0micrograms\/min<\/li>\n\n\n\n<li><strong>Convert micrograms to milligrams:<\/strong>Since 1 milligram = 1,000 micrograms:Dose\u00a0(mg\/min)=10,000\u00a0micrograms\/min1,000\u00a0micrograms\/mg=10\u00a0mg\/min\\text{Dose (mg\/min)} = \\frac{10,000 \\text{ micrograms\/min}}{1,000 \\text{ micrograms\/mg}} = 10 \\text{ mg\/min}Dose\u00a0(mg\/min)=1,000\u00a0micrograms\/mg10,000\u00a0micrograms\/min\u200b=10\u00a0mg\/min<\/li>\n\n\n\n<li><strong>Calculate the total volume needed per minute:<\/strong>We have a solution of esmolol at 2.5 grams (or 2,500 mg) in 250 mL D5W.Concentration\u00a0(mg\/mL)=2,500\u00a0mg250\u00a0mL=10\u00a0mg\/mL\\text{Concentration (mg\/mL)} = \\frac{2,500 \\text{ mg}}{250 \\text{ mL}} = 10 \\text{ mg\/mL}Concentration\u00a0(mg\/mL)=250\u00a0mL2,500\u00a0mg\u200b=10\u00a0mg\/mLTo find the volume needed to deliver 10 mg per minute:Volume\u00a0(mL\/min)=Dose\u00a0(mg\/min)Concentration\u00a0(mg\/mL)\\text{Volume (mL\/min)} = \\frac{\\text{Dose (mg\/min)}}{\\text{Concentration (mg\/mL)}}Volume\u00a0(mL\/min)=Concentration\u00a0(mg\/mL)Dose\u00a0(mg\/min)\u200b Volume\u00a0(mL\/min)=10\u00a0mg\/min10\u00a0mg\/mL=1\u00a0mL\/min\\text{Volume (mL\/min)} = \\frac{10 \\text{ mg\/min}}{10 \\text{ mg\/mL}} = 1 \\text{ mL\/min}Volume\u00a0(mL\/min)=10\u00a0mg\/mL10\u00a0mg\/min\u200b=1\u00a0mL\/min<\/li>\n\n\n\n<li><strong>Convert the rate to mL per hour:<\/strong>To convert mL per minute to mL per hour:Rate\u00a0(mL\/hr)=Rate\u00a0(mL\/min)\u00d760\u00a0min\/hr\\text{Rate (mL\/hr)} = \\text{Rate (mL\/min)} \\times 60 \\text{ min\/hr}Rate\u00a0(mL\/hr)=Rate\u00a0(mL\/min)\u00d760\u00a0min\/hr Rate\u00a0(mL\/hr)=1\u00a0mL\/min\u00d760=60\u00a0mL\/hr\\text{Rate (mL\/hr)} = 1 \\text{ mL\/min} \\times 60 = 60 \\text{ mL\/hr}Rate\u00a0(mL\/hr)=1\u00a0mL\/min\u00d760=60\u00a0mL\/hr<\/li>\n<\/ol>\n\n\n\n<p>Therefore, the nurse should program the IV pump to deliver the esmolol infusion at a rate of <strong>60 mL\/hr<\/strong>.<\/p>\n\n\n\n<p>So, the correct answer is <strong>B. 60 mL\/hr<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>A patient is receiving an IV of esmolol 2.5 grams in 250 mL D5W (dextrose 5% in water) infusing at 200 micrograms\/kilogram\/minute. The patient weighs 110 lb. What rate (in mL\/hr) should the nurse program into the IV pump to deliver this dose? A.45 mL\/hr B.60 mL\/hr C.75 mL\/hr D.90 mL\/hr The Correct Answer and [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-136218","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/136218","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=136218"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/136218\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=136218"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=136218"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=136218"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}