A nurse is preparing to administer ketorolac 0.4 mg\/kg IM to an adolescent who weighs 96.8 Ib. The amount available is ketorolac 15 mg\/mL. How many mL should the nurse administer? (Round the answer to the nearest tenth. Use a leading zero if it applies. Do not use a trailing zero.)<\/p>\n\n\n\n
The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n To solve this problem, we will go step by step to determine how many milliliters of ketorolac the nurse should administer based on the given dosage and the adolescent\u2019s weight.<\/p>\n\n\n\n Since the adolescent weighs 96.8 pounds (lb) and the conversion factor from pounds to kilograms is 1 kg = 2.2 lb, we divide the weight in pounds by 2.2 to convert to kilograms.<\/p>\n\n\n\n [ The prescribed dosage of ketorolac is 0.4 mg\/kg. To determine the total dosage in milligrams, multiply the weight in kilograms by the dosage per kilogram.<\/p>\n\n\n\n [ The medication available is ketorolac 15 mg\/mL. This means that every 1 mL of the solution contains 15 mg of ketorolac. To determine how many milliliters to administer, divide the total prescribed dosage by the concentration of the solution (15 mg\/mL).<\/p>\n\n\n\n [ When rounding 1.173 mL to the nearest tenth, the answer is 1.2 mL.<\/p>\n\n\n\n The nurse should administer 1.2 mL<\/strong> of ketorolac.<\/p>\n\n\n\n The calculation follows a standard procedure used in medication dosage determination, particularly in pediatrics, where weight-based dosing is common. First, the adolescent’s weight was converted from pounds to kilograms to fit the 0.4 mg\/kg dosage requirement. The total dose of 17.6 mg was calculated, and this was divided by the concentration of the ketorolac solution (15 mg\/mL) to determine the volume to administer. Rounding to the nearest tenth ensures accuracy without excessive precision that is unnecessary for the clinical setting.<\/p>\n","protected":false},"excerpt":{"rendered":" A nurse is preparing to administer ketorolac 0.4 mg\/kg IM to an adolescent who weighs 96.8 Ib. The amount available is ketorolac 15 mg\/mL. How many mL should the nurse administer? (Round the answer to the nearest tenth. Use a leading zero if it applies. Do not use a trailing zero.) The Correct Answer and […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-139492","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/139492","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=139492"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/139492\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=139492"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=139492"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=139492"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}Step 1: Convert the adolescent’s weight from pounds to kilograms.<\/h3>\n\n\n\n
\\text{Weight in kilograms} = \\frac{96.8 \\, \\text{lb}}{2.2} = 44 \\, \\text{kg}
]<\/p>\n\n\n\nStep 2: Calculate the prescribed dosage in milligrams.<\/h3>\n\n\n\n
\\text{Dosage in mg} = 0.4 \\, \\text{mg\/kg} \\times 44 \\, \\text{kg} = 17.6 \\, \\text{mg}
]<\/p>\n\n\n\nStep 3: Determine the volume of medication to administer.<\/h3>\n\n\n\n
\\text{Volume in mL} = \\frac{17.6 \\, \\text{mg}}{15 \\, \\text{mg\/mL}} = 1.173 \\, \\text{mL}
]<\/p>\n\n\n\nStep 4: Round the answer to the nearest tenth.<\/h3>\n\n\n\n
Final Answer:<\/h3>\n\n\n\n
Explanation:<\/h3>\n\n\n\n