A client is receiving IV dextrose 5% in water (D5W) at 125 mL\/hour and a secondary infusion of pantoprazole 40 mg IV daily. The pharmacy provides a 110 mL premixed solution of pantoprazole to be infused over 15 minutes. The nurse should program the secondary infusion to deliver how many mL\/hour? (Enter numeric value only.)<\/p>\n\n\n\n
The correct answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n To calculate the infusion rate for the secondary infusion of pantoprazole, we need to follow these steps:<\/p>\n\n\n\n Thus, the nurse should program the secondary infusion to deliver at a rate of 440 mL\/hour<\/strong>.<\/p>\n\n\n\n The calculation involves straightforward division. Infusion rates are calculated by dividing the total volume of the medication by the time it is to be infused. Here, the total volume of pantoprazole is 110 mL, and it needs to be infused in 15 minutes, which converts to 0.25 hours. By dividing 110 mL by 0.25 hours, you get the infusion rate of 440 mL\/hour. This ensures that the medication is delivered within the prescribed time frame and maintains proper dosing for the client.<\/p>\n","protected":false},"excerpt":{"rendered":" A client is receiving IV dextrose 5% in water (D5W) at 125 mL\/hour and a secondary infusion of pantoprazole 40 mg IV daily. The pharmacy provides a 110 mL premixed solution of pantoprazole to be infused over 15 minutes. The nurse should program the secondary infusion to deliver how many mL\/hour? (Enter numeric value only.) 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The pharmacy provides 110 mL of pantoprazole solution.<\/li>\n\n\n\n
The pantoprazole solution should be infused over 15 minutes.<\/li>\n\n\n\n
Since infusion rates are typically calculated in mL\/hour, convert 15 minutes into hours:
[
\\text{15 minutes} = \\frac{15}{60} \\text{ hours} = 0.25 \\text{ hours}
]<\/li>\n\n\n\n
To find the infusion rate in mL\/hour, use the formula:
[
\\text{Infusion rate (mL\/hour)} = \\frac{\\text{Total volume (mL)}}{\\text{Time (hours)}}
]
Plug in the values:
[
\\text{Infusion rate} = \\frac{110 \\text{ mL}}{0.25 \\text{ hours}} = 440 \\text{ mL\/hour}
]<\/li>\n<\/ol>\n\n\n\nExplanation<\/h3>\n\n\n\n