The density of mineral oil is 0.835 g\/mL. what is the mass in grams of a sample of mineral oil that has a volume of 3.50 mL.<\/p>\n\n\n\n
The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n To find the mass of a sample of mineral oil given its volume and density, we can use the formula for density:<\/p>\n\n\n\n [ From this formula, we can rearrange it to solve for mass:<\/p>\n\n\n\n [ In this case, we know the density of mineral oil is (0.835 \\, \\text{g\/mL}), and the volume of the mineral oil sample is (3.50 \\, \\text{mL}).<\/p>\n\n\n\n The mass of the mineral oil sample is 2.92 grams<\/strong>.<\/p>\n\n\n\n Understanding the relationship between density, mass, and volume is fundamental in various scientific disciplines, especially chemistry and physics. Density is a property of materials that describes how much mass is contained in a given volume. For liquids like mineral oil, density is typically expressed in grams per milliliter (g\/mL).<\/p>\n\n\n\n In practical applications, calculating mass from density and volume is crucial for tasks like formulation, quality control, and inventory management. For instance, knowing how much mineral oil is needed for a specific application helps in ensuring safety, efficiency, and cost-effectiveness. This calculation is also applicable in various industries, including pharmaceuticals, food production, and chemical manufacturing, highlighting the importance of accurate density measurements in everyday practice.<\/p>\n","protected":false},"excerpt":{"rendered":" The density of mineral oil is 0.835 g\/mL. what is the mass in grams of a sample of mineral oil that has a volume of 3.50 mL. The Correct Answer and Explanation is : To find the mass of a sample of mineral oil given its volume and density, we can use the formula for […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-145066","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/145066","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=145066"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/145066\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=145066"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=145066"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=145066"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
\\text{Density} = \\frac{\\text{Mass}}{\\text{Volume}}
]<\/p>\n\n\n\n
\\text{Mass} = \\text{Density} \\times \\text{Volume}
]<\/p>\n\n\n\nStep-by-Step Calculation<\/h3>\n\n\n\n
\n
\n
\n
[
\\text{Mass} = d \\times V
]
Substituting the values into the formula:
[
\\text{Mass} = 0.835 \\, \\text{g\/mL} \\times 3.50 \\, \\text{mL}
]<\/li>\n\n\n\n
[
\\text{Mass} = 2.9225 \\, \\text{g}
]<\/li>\n\n\n\n
Since the precision of the measurements is up to three significant figures, we round (2.9225 \\, \\text{g}) to (2.92 \\, \\text{g}).<\/li>\n<\/ol>\n\n\n\nFinal Answer<\/h3>\n\n\n\n
Explanation<\/h3>\n\n\n\n