{"id":147179,"date":"2024-10-02T14:04:45","date_gmt":"2024-10-02T14:04:45","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=147179"},"modified":"2024-10-02T14:04:47","modified_gmt":"2024-10-02T14:04:47","slug":"mining-companies-use-this-reaction-to-obtain-iron-from-iron-ore","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2024\/10\/02\/mining-companies-use-this-reaction-to-obtain-iron-from-iron-ore\/","title":{"rendered":"Mining companies use this reaction to obtain iron from iron ore"},"content":{"rendered":"\n<p>Mining companies use this reaction to obtain iron from iron ore: Fe2O3(s)+3CO(g) \u2192 2Fe(s)+3CO2(g) The reaction of 177 g of Fe2O3 with 82.8 g of CO produces 72.7 g of Fe. Calculate the theoretical yield of solid iron.<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>To calculate the theoretical yield of solid iron ((Fe)) from the reaction of iron(III) oxide ((Fe_2O_3)) with carbon monoxide ((CO)), we will follow these steps:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Identify the Balanced Chemical Equation<\/strong>:<br>The reaction is already balanced:<br>[<br>Fe_2O_3(s) + 3CO(g) \\rightarrow 2Fe(s) + 3CO_2(g)<br>]<\/li>\n\n\n\n<li><strong>Calculate Molar Masses<\/strong>:<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Molar mass of (Fe_2O_3):\n<ul class=\"wp-block-list\">\n<li>(Fe: 55.85 \\, g\/mol)<\/li>\n\n\n\n<li>(O: 16.00 \\, g\/mol)<br>[<br>\\text{Molar mass of } Fe_2O_3 = (2 \\times 55.85) + (3 \\times 16.00) = 159.7 \\, g\/mol<br>]<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Molar mass of (CO):<br>[<br>\\text{Molar mass of } CO = 12.01 + 16.00 = 28.01 \\, g\/mol<br>]<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Convert Masses to Moles<\/strong>:<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Moles of (Fe_2O_3):<br>[<br>\\text{Moles of } Fe_2O_3 = \\frac{177 \\, g}{159.7 \\, g\/mol} \\approx 1.107 \\, mol<br>]<\/li>\n\n\n\n<li>Moles of (CO):<br>[<br>\\text{Moles of } CO = \\frac{82.8 \\, g}{28.01 \\, g\/mol} \\approx 2.957 \\, mol<br>]<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Determine the Limiting Reactant<\/strong>:<br>From the balanced equation, (1 \\, mol \\, Fe_2O_3) reacts with (3 \\, mol \\, CO). Thus:<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>For 1.107 moles of (Fe_2O_3), we need:<br>[<br>1.107 \\, mol \\times 3 = 3.321 \\, mol \\, CO<br>]<br>Since we only have 2.957 moles of (CO), (CO) is the limiting reactant.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Calculate Theoretical Yield of Iron<\/strong>:<br>From the balanced equation, (3 \\, mol \\, CO) produces (2 \\, mol \\, Fe):<br>[<br>\\text{Moles of } Fe = \\frac{2}{3} \\times \\text{Moles of } CO = \\frac{2}{3} \\times 2.957 \\approx 1.972 \\, mol \\, Fe<br>] The molar mass of (Fe) is (55.85 \\, g\/mol):<br>[<br>\\text{Theoretical yield of } Fe = 1.972 \\, mol \\times 55.85 \\, g\/mol \\approx 110.0 \\, g<br>]<\/li>\n<\/ol>\n\n\n\n<h3 class=\"wp-block-heading\">Conclusion<\/h3>\n\n\n\n<p>The theoretical yield of solid iron from the reaction is <strong>110.0 grams<\/strong>. This calculation demonstrates the importance of determining the limiting reactant in a chemical reaction, as it dictates the maximum amount of product that can be formed. Despite having a sufficient quantity of (Fe_2O_3), the limited amount of (CO) restricts the formation of (Fe). Understanding stoichiometry allows chemists to predict yields and optimize the usage of reactants in industrial processes.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Mining companies use this reaction to obtain iron from iron ore: Fe2O3(s)+3CO(g) \u2192 2Fe(s)+3CO2(g) The reaction of 177 g of Fe2O3 with 82.8 g of CO produces 72.7 g of Fe. Calculate the theoretical yield of solid iron. The Correct Answer and Explanation is : To calculate the theoretical yield of solid iron ((Fe)) from [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-147179","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/147179","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=147179"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/147179\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=147179"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=147179"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=147179"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}