{"id":149055,"date":"2024-10-06T17:02:45","date_gmt":"2024-10-06T17:02:45","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=149055"},"modified":"2024-10-06T17:03:35","modified_gmt":"2024-10-06T17:03:35","slug":"what-is-the-total-mass-of-iron-in-1-0-mole-of-fe203","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2024\/10\/06\/what-is-the-total-mass-of-iron-in-1-0-mole-of-fe203\/","title":{"rendered":"What is the total mass of iron in 1.0 mole of Fe203"},"content":{"rendered":"\n<p>What is the total mass of iron in 1.0 mole of Fe203?<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>The correct answer is:  <strong>111.70 g<\/strong>.<\/p>\n\n\n\n<p>To find the total mass of iron (Fe) in 1 mole of iron(III) oxide (Fe\u2082O\u2083), follow these steps:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">1. Determine the Molar Mass of Fe\u2082O\u2083<\/h3>\n\n\n\n<p>The molecular formula for iron(III) oxide is Fe\u2082O\u2083, which contains 2 iron (Fe) atoms and 3 oxygen (O) atoms. First, calculate the molar mass of Fe\u2082O\u2083 by summing the atomic masses of its elements.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The atomic mass of iron (Fe) is approximately 55.85 g\/mol.<\/li>\n\n\n\n<li>The atomic mass of oxygen (O) is approximately 16.00 g\/mol.<\/li>\n<\/ul>\n\n\n\n<p>The molar mass of Fe\u2082O\u2083 = (2 \u00d7 55.85 g\/mol) + (3 \u00d7 16.00 g\/mol)<br>= 111.70 g\/mol (for Fe) + 48.00 g\/mol (for O)<br>= <strong>159.70 g\/mol<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">2. Calculate the Total Mass of Iron in Fe\u2082O\u2083<\/h3>\n\n\n\n<p>We know that Fe\u2082O\u2083 contains 2 atoms of iron. Since each mole of Fe\u2082O\u2083 contains 2 moles of iron atoms, we can calculate the mass of iron in 1 mole of Fe\u2082O\u2083 by considering just the iron portion of the molar mass.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The mass of 2 moles of iron is:<br>2 \u00d7 55.85 g = <strong>111.70 g<\/strong>.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">3. Conclusion<\/h3>\n\n\n\n<p>The total mass of iron in 1 mole of Fe\u2082O\u2083 is <strong>111.70 g<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>Iron(III) oxide (Fe\u2082O\u2083) is a compound composed of iron and oxygen. To determine the mass of iron in 1 mole of Fe\u2082O\u2083, you need to first calculate the molar mass of the entire compound by adding the masses of its constituent atoms. Since Fe\u2082O\u2083 contains 2 atoms of iron and 3 atoms of oxygen, the next step is to focus on the mass of iron alone. For every mole of Fe\u2082O\u2083, there are 2 moles of iron atoms, which weigh a total of 111.70 grams. This is important in various fields such as chemistry, metallurgy, and environmental science where precise stoichiometric calculations are required for reactions involving iron(III) oxide.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>What is the total mass of iron in 1.0 mole of Fe203? The Correct Answer and Explanation is : The correct answer is: 111.70 g. To find the total mass of iron (Fe) in 1 mole of iron(III) oxide (Fe\u2082O\u2083), follow these steps: 1. Determine the Molar Mass of Fe\u2082O\u2083 The molecular formula for iron(III) [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-149055","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/149055","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=149055"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/149055\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=149055"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=149055"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=149055"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}