Simplify square root of 63<\/p>\n\n\n\n
The Correct answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n The correct answer is: {3\\sqrt{7}}<\/strong><\/mark><\/p>\n\n\n\n The simplified form of the square root of 63 is:<\/p>\n\n\n\n [ Simplifying square roots is important because it expresses the root in a more manageable form, making it easier to work with in equations or other math problems. In real-life applications, such as engineering, physics, or construction, this simplification helps in making calculations faster and clearer.<\/p>\n\n\n\n This process follows the rule of identifying and pulling out perfect squares, leaving the non-perfect square factors under the square root.<\/p>\n","protected":false},"excerpt":{"rendered":" Simplify square root of 63 The Correct answer and Explanation is : The correct answer is: {3\\sqrt{7}} The simplified form of the square root of 63 is: [\\sqrt{63} = \\sqrt{9 \\times 7} = \\sqrt{9} \\times \\sqrt{7} = 3\\sqrt{7}] Explanation Why Simplify Square Roots? Simplifying square roots is important because it expresses the root in a […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-149867","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/149867","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=149867"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/149867\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=149867"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=149867"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=149867"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
\\sqrt{63} = \\sqrt{9 \\times 7} = \\sqrt{9} \\times \\sqrt{7} = 3\\sqrt{7}
]<\/p>\n\n\n\nExplanation<\/h3>\n\n\n\n
\n
To simplify a square root, first break down the number into its prime factors. For 63, the prime factorization is:
[
63 = 9 \\times 7
]
We split 63 into the product of 9 and 7 because 9 is a perfect square.<\/li>\n\n\n\n
We can take the square root of any perfect square easily. Since 9 is a perfect square, its square root is:
[
\\sqrt{9} = 3
]<\/li>\n\n\n\n
Using the property of square roots, we can split the original square root as:
[
\\sqrt{63} = \\sqrt{9 \\times 7} = \\sqrt{9} \\times \\sqrt{7}
]
Now, substitute the value of (\\sqrt{9}):
[
\\sqrt{63} = 3 \\times \\sqrt{7}
]<\/li>\n\n\n\n
Since (\\sqrt{7}) is not a perfect square and cannot be simplified further, the final simplified form of (\\sqrt{63}) is:
[
\\boxed{3\\sqrt{7}}
]<\/li>\n<\/ol>\n\n\n\nWhy Simplify Square Roots?<\/h3>\n\n\n\n