{"id":150095,"date":"2024-10-08T11:34:33","date_gmt":"2024-10-08T11:34:33","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=150095"},"modified":"2024-10-08T11:34:36","modified_gmt":"2024-10-08T11:34:36","slug":"consider-nitrous-acid-hno%e2%82%82-hono","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2024\/10\/08\/consider-nitrous-acid-hno%e2%82%82-hono\/","title":{"rendered":"Consider nitrous acid, HNO\u2082 (HONO)"},"content":{"rendered":"\n<p>Consider nitrous acid, HNO\u2082 (HONO)<br>What is the molecular geometry of the nitrogen in HNO2?<br>A Octahedral<br>B Triangular planar<br>C Linear<br>D Tetrahedral<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>The correct answer is <strong>B: Triangular planar<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>To determine the molecular geometry of the nitrogen atom in nitrous acid (HNO\u2082), we first need to analyze the structure of the molecule. Nitrous acid has the following structural formula:<\/p>\n\n\n\n<p>[ H &#8211; N = O ]<br>[ \\ \\ \\ \\ | ]<br>[ \\ \\ \\ \\ O ]<\/p>\n\n\n\n<p>In this structure, the nitrogen (N) atom is bonded to two oxygen (O) atoms and one hydrogen (H) atom.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Steps to Determine Geometry:<\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Count the Valence Electrons:<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Nitrogen has 5 valence electrons.<\/li>\n\n\n\n<li>Each oxygen contributes 6 valence electrons (total of 12 for two oxygens).<\/li>\n\n\n\n<li>Hydrogen contributes 1 valence electron.<\/li>\n\n\n\n<li>Total: ( 5 + 12 + 1 = 18 ) valence electrons.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Determine the Number of Bonding and Lone Pairs:<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>In HNO\u2082, nitrogen forms one double bond with one oxygen and a single bond with the other oxygen (which also bonds to hydrogen).<\/li>\n\n\n\n<li>Therefore, nitrogen is involved in three bonding pairs (two single bonds and one double bond).<\/li>\n\n\n\n<li>Since nitrogen has 5 valence electrons, and it uses 3 for bonding, it will have ( 5 &#8211; 3 = 2 ) remaining electrons, which form a lone pair.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Use VSEPR Theory:<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>According to the Valence Shell Electron Pair Repulsion (VSEPR) theory, the geometry around the nitrogen atom is determined by the arrangement of the regions of electron density (bonding pairs and lone pairs).<\/li>\n\n\n\n<li>The nitrogen atom has three regions of electron density (two single bonds and one double bond) and one lone pair.<\/li>\n\n\n\n<li>The arrangement of these regions results in a <strong>trigonal planar<\/strong> geometry, where the bond angles are approximately 120 degrees.<\/li>\n<\/ul>\n\n\n\n<p>In conclusion, the molecular geometry of nitrogen in HNO\u2082 is <strong>trigonal planar<\/strong> due to the presence of three bonding pairs and one lone pair, which leads to this specific geometric arrangement.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Consider nitrous acid, HNO\u2082 (HONO)What is the molecular geometry of the nitrogen in HNO2?A OctahedralB Triangular planarC LinearD Tetrahedral The Correct Answer and Explanation is : The correct answer is B: Triangular planar. Explanation: To determine the molecular geometry of the nitrogen atom in nitrous acid (HNO\u2082), we first need to analyze the structure of [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-150095","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/150095","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=150095"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/150095\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=150095"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=150095"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=150095"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}