What is the unit weight of water in kg m3?<\/p>\n\n\n\n
The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n The unit weight of water is approximately 1,000 kg\/m\u00b3<\/strong> at standard temperature and pressure conditions (specifically at 4 degrees Celsius). This value is crucial in various scientific and engineering applications, including fluid mechanics, civil engineering, and environmental science.<\/p>\n\n\n\n Density and Unit Weight<\/strong>: The unit weight of a substance is closely related to its density. Density (( \\rho )) is defined as mass (( m )) per unit volume (( V )), given by the formula:<\/p>\n\n\n\n [ For water, at its maximum density (4\u00b0C), the density is about 1,000 kg\/m\u00b3, meaning one cubic meter of water has a mass of 1,000 kilograms. Unit weight (( \\gamma )) is defined as the weight of a substance per unit volume. It can be calculated using the formula:<\/p>\n\n\n\n [ where ( g ) is the acceleration due to gravity (approximately 9.81 m\/s\u00b2). When substituting the density of water, the unit weight of water becomes:<\/p>\n\n\n\n [ Importance in Applications<\/strong>: Understanding the unit weight of water is essential in many fields. In civil engineering, it helps in calculating the buoyant forces acting on submerged objects and determining the load-bearing capacity of soils. In environmental science, it assists in modeling the behavior of water in natural systems, including rivers and lakes.<\/p>\n\n\n\n Variations<\/strong>: The unit weight of water can vary slightly with changes in temperature and salinity. For example, seawater, which contains salts and other dissolved substances, has a higher density (around 1,025 kg\/m\u00b3) than pure water, leading to a greater unit weight.<\/p>\n\n\n\n In summary, the unit weight of water at standard conditions is about 1,000 kg\/m\u00b3, making it a fundamental value in physics and engineering.<\/p>\n","protected":false},"excerpt":{"rendered":" What is the unit weight of water in kg m3? The Correct Answer and Explanation is : The unit weight of water is approximately 1,000 kg\/m\u00b3 at standard temperature and pressure conditions (specifically at 4 degrees Celsius). This value is crucial in various scientific and engineering applications, including fluid mechanics, civil engineering, and environmental science. […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-151554","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/151554","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=151554"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/151554\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=151554"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=151554"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=151554"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}Explanation<\/h3>\n\n\n\n
\\rho = \\frac{m}{V}
]<\/p>\n\n\n\n
\\gamma = \\rho \\cdot g
]<\/p>\n\n\n\n
\\gamma = 1,000 \\text{ kg\/m\u00b3} \\times 9.81 \\text{ m\/s\u00b2} \\approx 9,810 \\text{ N\/m\u00b3}
]<\/p>\n\n\n\n