A ball has a mass of 2.0 kg. The ball approaches a wall at a speed of 3.0 m\/s and rebounds at a
speed of 1.0m\/s.
wall
What is the impulse on the wall?
A 4.0N
B 4.0NS
C 8.0N
D 8.0Ns<\/p>\n\n\n\n
The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n The correct answer is:D) 8.0 Ns.<\/strong><\/p>\n\n\n\n To find the impulse on the wall due to the ball’s collision, we first need to understand the relationship between impulse, momentum, and the change in velocity of the ball.<\/p>\n\n\n\n Impulse ((J)) is defined as the change in momentum of an object, which can also be expressed as the product of the average force ((F)) applied over a time interval ((t)), or as the change in momentum:<\/p>\n\n\n\n [ where momentum ((p)) is given by the product of mass ((m)) and velocity ((v)):<\/p>\n\n\n\n [ In this case, the mass of the ball ((m)) is (2.0 \\, \\text{kg}).<\/p>\n\n\n\n [ Since the ball rebounds in the opposite direction, we consider the final velocity to be negative:<\/p>\n\n\n\n [ Now, we calculate the change in momentum:<\/p>\n\n\n\n [ The negative sign indicates that the momentum has changed direction, but impulse (as a magnitude) is simply taken as a positive value, thus:<\/p>\n\n\n\n [ Thus, the impulse on the wall is 8.0 Ns<\/strong>. Therefore, the correct answer is:<\/p>\n\n\n\n D) 8.0 Ns.<\/strong><\/p>\n\n\n\n In conclusion, the impulse on the wall due to the collision is equal to the change in momentum of the ball. Since the ball’s momentum changes from a positive value to a negative value upon rebounding, the magnitude of the impulse experienced by the wall is (8.0 \\, \\text{Ns}).<\/p>\n","protected":false},"excerpt":{"rendered":" A ball has a mass of 2.0 kg. The ball approaches a wall at a speed of 3.0 m\/s and rebounds at aspeed of 1.0m\/s.wallWhat is the impulse on the wall?A 4.0NB 4.0NSC 8.0ND 8.0Ns The Correct Answer and Explanation is : The correct answer is:D) 8.0 Ns. To find the impulse on the wall […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-152284","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/152284","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=152284"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/152284\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=152284"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=152284"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=152284"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
J = \\Delta p = p_{final} – p_{initial}
]<\/p>\n\n\n\n
p = mv
]<\/p>\n\n\n\n\n
p_{initial} = m \\cdot v_{initial} = 2.0 \\, \\text{kg} \\cdot 3.0 \\, \\text{m\/s} = 6.0 \\, \\text{kg m\/s}
]<\/p>\n\n\n\n\n
p_{final} = m \\cdot v_{final} = 2.0 \\, \\text{kg} \\cdot (-1.0 \\, \\text{m\/s}) = -2.0 \\, \\text{kg m\/s}
]<\/p>\n\n\n\n\n
\\Delta p = p_{final} – p_{initial} = -2.0 \\, \\text{kg m\/s} – 6.0 \\, \\text{kg m\/s} = -8.0 \\, \\text{kg m\/s}
]<\/p>\n\n\n\n
|J| = 8.0 \\, \\text{Ns}
]<\/p>\n\n\n\n