The equation of a line is y=15x\u22127. What are the coordinates of the point where the line crosses the y-axis?<\/p>\n\n\n\n
The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n To find the coordinates of the point where the line ( y = 15x – 7 ) crosses the y-axis, we need to determine the value of ( y ) when ( x = 0 ). This point is referred to as the y-intercept.<\/p>\n\n\n\n In conclusion, the coordinates of the point where the line ( y = 15x – 7 ) crosses the y-axis are ( (0, -7) ). This point serves as a crucial reference for understanding the line’s behavior and position in the Cartesian plane.<\/p>\n","protected":false},"excerpt":{"rendered":" The equation of a line is y=15x\u22127. What are the coordinates of the point where the line crosses the y-axis? The Correct Answer and Explanation is : To find the coordinates of the point where the line ( y = 15x – 7 ) crosses the y-axis, we need to determine the value of ( […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-153236","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/153236","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=153236"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/153236\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=153236"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=153236"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=153236"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}\n
We substitute ( x = 0 ) into the equation of the line:
[
y = 15(0) – 7
]
Simplifying this gives:
[
y = 0 – 7 = -7
]<\/li>\n\n\n\n
Therefore, the coordinates of the point where the line crosses the y-axis are:
[
(0, -7)
]<\/li>\n\n\n\n
The y-axis is the vertical line where ( x = 0 ) for all values of ( y ). A line crosses the y-axis only once, which occurs at the y-intercept. The y-intercept is critical because it gives us information about the behavior of the line; specifically, it indicates where the line starts when graphed.<\/li>\n\n\n\n
The equation ( y = 15x – 7 ) is in slope-intercept form ( y = mx + b ), where ( m ) represents the slope and ( b ) represents the y-intercept. In this case, the slope ( m = 15 ) indicates that for every unit increase in ( x ), ( y ) increases by 15 units. The y-intercept ( b = -7 ) tells us that the line crosses the y-axis at ( y = -7 ).<\/li>\n\n\n\n
If you were to graph this line, you would plot the point ( (0, -7) ) on the y-axis. From this point, you could use the slope to find other points on the line. For example, moving right 1 unit (to ( x = 1 )), the line would rise 15 units to ( y = 8 ).<\/li>\n<\/ol>\n\n\n\n