{"id":155642,"date":"2024-10-16T08:57:04","date_gmt":"2024-10-16T08:57:04","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=155642"},"modified":"2024-10-16T08:57:06","modified_gmt":"2024-10-16T08:57:06","slug":"hybridization-of-i-in-if5-is","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2024\/10\/16\/hybridization-of-i-in-if5-is\/","title":{"rendered":"Hybridization of I in IF5 is"},"content":{"rendered":"\n<p>Hybridization of I in IF5 is? <\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>The hybridization of iodine (I) in <strong>IF\u2085<\/strong> is <strong>sp\u00b3d\u00b2<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<h4 class=\"wp-block-heading\">Step 1: Valence Electrons<\/h4>\n\n\n\n<p>Iodine is in group 17 of the periodic table and has 7 valence electrons. Fluorine, also in group 17, has 7 valence electrons but forms a single bond with iodine, using 1 electron from each atom.<\/p>\n\n\n\n<p>Since there are 5 fluorine atoms in IF\u2085, each forms a single bond with iodine, accounting for 5 of iodine\u2019s 7 valence electrons.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">Step 2: Lone Pairs<\/h4>\n\n\n\n<p>After forming 5 bonds with fluorine, iodine has 2 electrons (1 pair) left. These will remain as a lone pair on iodine.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">Step 3: Electron Geometry<\/h4>\n\n\n\n<p>To determine the hybridization, we use the concept of <strong>electron domains<\/strong> around the iodine atom. In IF\u2085, iodine has:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>5 bond pairs (due to the 5 bonds with fluorine atoms),<\/li>\n\n\n\n<li>1 lone pair (as discussed).<\/li>\n<\/ul>\n\n\n\n<p>That gives a total of <strong>6 electron domains<\/strong>. For an atom with 6 electron domains, the corresponding hybridization is <strong>sp\u00b3d\u00b2<\/strong>.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">Step 4: Shape and Bond Angles<\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The molecular geometry is <strong>square pyramidal<\/strong>, as derived from the octahedral electron geometry but with one position occupied by a lone pair.<\/li>\n\n\n\n<li>In this arrangement, the lone pair will take an equatorial position, minimizing electron-electron repulsion with the bonding pairs.<\/li>\n\n\n\n<li>The bond angles around the iodine atom are slightly less than 90\u00b0 due to the lone pair\u2019s repulsion.<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\">Orbitals in sp\u00b3d\u00b2 Hybridization<\/h4>\n\n\n\n<p>In sp\u00b3d\u00b2 hybridization, the orbitals involved are:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>1 s orbital,<\/li>\n\n\n\n<li>3 p orbitals,<\/li>\n\n\n\n<li>2 d orbitals.<\/li>\n<\/ul>\n\n\n\n<p>These combine to form 6 hybrid orbitals, accommodating 5 fluorine atoms and 1 lone pair on iodine.<\/p>\n\n\n\n<p>Therefore, iodine in IF\u2085 is <strong>sp\u00b3d\u00b2<\/strong> hybridized, forming a square pyramidal structure.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Hybridization of I in IF5 is? The Correct Answer and Explanation is : The hybridization of iodine (I) in IF\u2085 is sp\u00b3d\u00b2. Explanation: Step 1: Valence Electrons Iodine is in group 17 of the periodic table and has 7 valence electrons. Fluorine, also in group 17, has 7 valence electrons but forms a single bond [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-155642","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/155642","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=155642"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/155642\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=155642"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=155642"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=155642"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}