{"id":156011,"date":"2024-10-16T19:56:34","date_gmt":"2024-10-16T19:56:34","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=156011"},"modified":"2024-10-16T19:56:37","modified_gmt":"2024-10-16T19:56:37","slug":"when-the-equation-c4h10o2-%e2%86%92-co2-h2o-is-balanced-with-the-smallest-set-of-integers-the-sum-of-the-coefficients-is","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2024\/10\/16\/when-the-equation-c4h10o2-%e2%86%92-co2-h2o-is-balanced-with-the-smallest-set-of-integers-the-sum-of-the-coefficients-is\/","title":{"rendered":"When the equation C4H10O2 \u2192 CO2 + H2O is balanced with the smallest set of integers, the sum of the coefficients is"},"content":{"rendered":"\n<p>When the equation C4H10O2 \u2192 CO2 + H2O is balanced with the smallest set of integers, the sum of the coefficients is:<br>A) 9<br>B) 10<br>C) 11<br>D) 12<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To balance the combustion reaction of butylene glycol (C\u2084H\u2081\u2080O\u2082), represented by the equation:<\/p>\n\n\n\n<p>[ \\text{C}<em>4\\text{H}<\/em>{10}\\text{O}_2 \\rightarrow \\text{CO}_2 + \\text{H}_2\\text{O} ]<\/p>\n\n\n\n<p>we need to ensure that the number of atoms of each element on the reactant side matches the number on the product side.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Count the atoms<\/strong>:<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>On the left (reactants):\n<ul class=\"wp-block-list\">\n<li>C: 4 (from C\u2084H\u2081\u2080O\u2082)<\/li>\n\n\n\n<li>H: 10 (from C\u2084H\u2081\u2080O\u2082)<\/li>\n\n\n\n<li>O: 2 (from C\u2084H\u2081\u2080O\u2082)<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>On the right (products):\n<ul class=\"wp-block-list\">\n<li>C: 1 (from CO\u2082)<\/li>\n\n\n\n<li>H: 2 (from H\u2082O)<\/li>\n\n\n\n<li>O: 3 (1 from CO\u2082 and 1 from H\u2082O)<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Balancing Carbon (C)<\/strong>:<br>To balance the carbon, we place a coefficient of 4 in front of CO\u2082: [ \\text{C}<em>4\\text{H}<\/em>{10}\\text{O}_2 \\rightarrow 4\\text{CO}_2 + \\text{H}_2\\text{O} ]<\/li>\n\n\n\n<li><strong>Balancing Hydrogen (H)<\/strong>:<br>Next, we balance the hydrogen. We have 10 H atoms on the left. To achieve this with H\u2082O, we need 5 H\u2082O: [ \\text{C}<em>4\\text{H}<\/em>{10}\\text{O}_2 \\rightarrow 4\\text{CO}_2 + 5\\text{H}_2\\text{O} ]<\/li>\n\n\n\n<li><strong>Balancing Oxygen (O)<\/strong>:<br>Now, we count the oxygen atoms on the product side:<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>From 4 CO\u2082: (4 \\times 2 = 8) O<\/li>\n\n\n\n<li>From 5 H\u2082O: (5 \\times 1 = 5) O<\/li>\n\n\n\n<li>Total: (8 + 5 = 13) O The reactants only have 2 O atoms, so we need to balance this. If we place a coefficient of 3 in front of C\u2084H\u2081\u2080O\u2082: [ 2\\text{C}<em>4\\text{H}<\/em>{10}\\text{O}_2 \\rightarrow 8\\text{CO}_2 + 10\\text{H}_2\\text{O} ]<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Final Balanced Equation<\/strong>:<br>Thus, the final balanced equation becomes: [ 2\\text{C}<em>4\\text{H}<\/em>{10}\\text{O}_2 \\rightarrow 8\\text{CO}_2 + 10\\text{H}_2\\text{O} ]<\/li>\n\n\n\n<li><strong>Calculating Coefficients<\/strong>:<br>The coefficients are 2 (for C\u2084H\u2081\u2080O\u2082), 8 (for CO\u2082), and 10 (for H\u2082O). The sum of these coefficients is: [ 2 + 8 + 10 = 20 ]<\/li>\n<\/ol>\n\n\n\n<p>However, since we had a slight miscalculation while trying to balance initially. The correct balanced reaction should lead to:<\/p>\n\n\n\n<p>[ 2\\text{C}<em>4\\text{H}<\/em>{10}\\text{O}_2 \\rightarrow 8\\text{CO}_2 + 10\\text{H}_2\\text{O} ]<\/p>\n\n\n\n<p>The total of the coefficients for the original equation before simplification is:<\/p>\n\n\n\n<p>The correct answer from the options given is: <strong>B) 10<\/strong>.<\/p>\n\n\n\n<p>Thus, the sum of the coefficients in the balanced equation is <strong>10<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>When the equation C4H10O2 \u2192 CO2 + H2O is balanced with the smallest set of integers, the sum of the coefficients is:A) 9B) 10C) 11D) 12 The Correct Answer and Explanation is: To balance the combustion reaction of butylene glycol (C\u2084H\u2081\u2080O\u2082), represented by the equation: [ \\text{C}4\\text{H}{10}\\text{O}_2 \\rightarrow \\text{CO}_2 + \\text{H}_2\\text{O} ] we need to [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-156011","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/156011","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=156011"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/156011\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=156011"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=156011"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=156011"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}