What is the vol in ml of 3lbs of mineral oil with a specific gravity of 0.85<\/p>\n\n\n\n
The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n To find the volume in milliliters (mL) of 3 pounds of mineral oil with a specific gravity of 0.85, we can use the relationship between mass, volume, and specific gravity.<\/p>\n\n\n\n The volume of 3 pounds of mineral oil with a specific gravity of 0.85 is approximately 1601.3 mL<\/strong>. This calculation illustrates how specific gravity provides a useful method for determining volume when the mass and specific gravity of a substance are known. It is essential in various applications, including pharmaceuticals, where precise measurements of liquids are crucial for formulation and dosing.<\/p>\n","protected":false},"excerpt":{"rendered":" What is the vol in ml of 3lbs of mineral oil with a specific gravity of 0.85 The Correct Answer and Explanation is : To find the volume in milliliters (mL) of 3 pounds of mineral oil with a specific gravity of 0.85, we can use the relationship between mass, volume, and specific gravity. Step-by-Step […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-156457","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/156457","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=156457"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/156457\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=156457"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=156457"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=156457"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}Step-by-Step Calculation<\/h3>\n\n\n\n
\n
Specific gravity (SG) is defined as the ratio of the density of a substance to the density of water. The density of water is approximately 1 g\/mL at room temperature. Therefore, if the specific gravity of mineral oil is 0.85, its density can be calculated as follows: [
\\text{Density of mineral oil} = \\text{SG} \\times \\text{Density of water} = 0.85 \\, \\text{g\/mL} \\times 1 \\, \\text{g\/mL} = 0.85 \\, \\text{g\/mL}
]<\/li>\n\n\n\n
Since 1 pound is approximately equal to 453.592 grams, we can convert 3 pounds to grams: [
3 \\, \\text{lbs} = 3 \\times 453.592 \\, \\text{g} = 1360.78 \\, \\text{g}
]<\/li>\n\n\n\n
We can now use the density to calculate the volume in mL. The formula for volume (V) is: [
V = \\frac{m}{\\text{density}}
] Where:<\/li>\n<\/ol>\n\n\n\n\n
V = \\frac{1360.78 \\, \\text{g}}{0.85 \\, \\text{g\/mL}} \\approx 1601.3 \\, \\text{mL}
]<\/li>\n<\/ul>\n\n\n\nConclusion<\/h3>\n\n\n\n