{"id":156552,"date":"2024-10-17T11:42:14","date_gmt":"2024-10-17T11:42:14","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=156552"},"modified":"2024-10-17T11:42:17","modified_gmt":"2024-10-17T11:42:17","slug":"which-hybridization-best-characterizes-the-atom-involved-in-a-c2h4-molecule","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2024\/10\/17\/which-hybridization-best-characterizes-the-atom-involved-in-a-c2h4-molecule\/","title":{"rendered":"Which hybridization best characterizes the atom involved in a C2H4 molecule"},"content":{"rendered":"\n

Which hybridization best characterizes the atom involved in a C2H4 molecule? sp b. a. sp? C. sp3 d. 4 sp<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

The correct answer for the hybridization that best characterizes the carbon atoms in a C\u2082H\u2084 molecule (ethylene) is a. sp\u00b2<\/strong>.<\/p>\n\n\n\n

Explanation:<\/h3>\n\n\n\n

C\u2082H\u2084, or ethylene, is an important organic compound that consists of two carbon (C) atoms and four hydrogen (H) atoms. In this molecule, each carbon atom forms three sigma (\u03c3) bonds: two with hydrogen atoms and one with the other carbon atom. To understand the hybridization of the carbon atoms in C\u2082H\u2084, we need to consider the bonding and geometry around each carbon atom.<\/p>\n\n\n\n

    \n
  1. Valence Electrons<\/strong>: Each carbon atom has four valence electrons. In ethylene, each carbon is bonded to two hydrogen atoms and one other carbon atom. This leads to a total of three bonding regions (the two C-H bonds and the C-C bond) and no lone pairs.<\/li>\n\n\n\n
  2. Hybridization Process<\/strong>: To form these bonds, the carbon atoms undergo hybridization. Since each carbon is involved in three bonding regions, we can determine the hybridization type:<\/li>\n<\/ol>\n\n\n\n
      \n
    • sp<\/strong> hybridization occurs when there are two bonding regions (linear geometry).<\/li>\n\n\n\n
    • sp\u00b2<\/strong> hybridization occurs when there are three bonding regions (trigonal planar geometry).<\/li>\n\n\n\n
    • sp\u00b3<\/strong> hybridization occurs when there are four bonding regions (tetrahedral geometry).<\/li>\n<\/ul>\n\n\n\n
        \n
      1. Geometry<\/strong>: The geometry around each carbon in C\u2082H\u2084 is trigonal planar, with bond angles of approximately 120 degrees. This is characteristic of sp\u00b2 hybridization, where one s orbital and two p orbitals combine to form three sp\u00b2 hybrid orbitals. These orbitals are oriented 120 degrees apart in a plane, allowing for the formation of \u03c3 bonds with hydrogen and the other carbon atom.<\/li>\n\n\n\n
      2. Double Bond Formation<\/strong>: Additionally, the C=C double bond in ethylene consists of one \u03c3 bond (formed by overlapping sp\u00b2 orbitals) and one \u03c0 bond (formed by the side-on overlap of the unhybridized p orbitals from each carbon).<\/li>\n<\/ol>\n\n\n\n

        In summary, due to the presence of three bonding regions and the trigonal planar geometry around each carbon atom, the hybridization of the carbon atoms in C\u2082H\u2084 is best described as sp\u00b2<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"

        Which hybridization best characterizes the atom involved in a C2H4 molecule? sp b. a. sp? C. sp3 d. 4 sp The Correct Answer and Explanation is: The correct answer for the hybridization that best characterizes the carbon atoms in a C\u2082H\u2084 molecule (ethylene) is a. sp\u00b2. Explanation: C\u2082H\u2084, or ethylene, is an important organic compound […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-156552","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/156552","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=156552"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/156552\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=156552"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=156552"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=156552"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}