Which equation represents a fission reaction?
A.
\\ce
0
1n+
92
235
\u200b
U\u2212>
55
140
\u200b
Cs+
37
94
\u200b
Rb+2
0
1
\u200b
n
B.
\\ce
2
4
\u200b
Be+
2
4
\u200b
He\u2212>
6
12
\u200b
C+
0
1
\u200b
n
C.
\\ce
93
233
\u200b
Np\u2212>
94
239
\u200b
Pu+e
\u2212<\/p>\n\n\n\n
The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n The correct answer is A<\/strong>:<\/p>\n\n\n\n [ Nuclear fission is the process where a heavy atomic nucleus splits into smaller nuclei along with the release of energy. This reaction typically occurs when a neutron collides with a heavy nucleus, such as uranium-235 ((^{235}{92}U)). In the equation given in option A, a neutron ((^{1}<\/em>{0}n)) interacts with uranium-235, leading to its fission.<\/p>\n\n\n\n Upon absorption of the neutron, the uranium nucleus becomes unstable and splits into two smaller nuclei, cesium-140 ((^{140}{55}Cs)) and rubidium-94 ((^{94}<\/em>{37}Rb)). Importantly, this fission reaction also releases two additional neutrons ((2^{1}_{0}n)) and a significant amount of energy, which is a hallmark of fission processes. This energy release is what makes fission a powerful source of energy for nuclear reactors and atomic bombs.<\/p>\n\n\n\n [ This reaction is an example of nuclear fusion, where two light nuclei combine to form a heavier nucleus (carbon-12, (^{12}_{6}C)) and a neutron. Fusion typically occurs in stars and involves the combination of light elements, contrasting sharply with fission, which deals with heavy elements.<\/p>\n\n\n\n [ This reaction represents beta decay, not fission. In beta decay, a neutron in the nucleus is converted into a proton while emitting a beta particle (electron, (e^{-})). Although related to nuclear processes, it does not involve the splitting of a nucleus into smaller fragments.<\/p>\n\n\n\n In summary, option A is the correct representation of a fission reaction, highlighting the critical nature of neutron interactions with heavy nuclei that lead to energy release.<\/p>\n","protected":false},"excerpt":{"rendered":" Which equation represents a fission reaction?A.\\ce01n+92235\u200bU\u2212>55140\u200bCs+3794\u200bRb+201\u200bnB.\\ce24\u200bBe+24\u200bHe\u2212>612\u200bC+01\u200bnC.\\ce93233\u200bNp\u2212>94239\u200bPu+e\u2212 The Correct Answer and Explanation is : The correct answer is A: [\\ce{^{235}{92}U + ^{1}{0}n -> ^{140}{55}Cs + ^{94}{37}Rb + 2^{1}_{0}n}] Explanation of Fission Reactions Nuclear fission is the process where a heavy atomic nucleus splits into smaller nuclei along with the release of energy. This reaction typically occurs […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-159707","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/159707","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=159707"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/159707\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=159707"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=159707"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=159707"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
\\ce{^{235}{92}U + ^{1}<\/em>{0}n -> ^{140}{55}Cs + ^{94}<\/em>{37}Rb + 2^{1}_{0}n}
]<\/p>\n\n\n\nExplanation of Fission Reactions<\/h3>\n\n\n\n
Analyzing the Other Options<\/h3>\n\n\n\n
\n
\\ce{^{4}{2}Be + ^{4}<\/em>{2}He -> ^{12}{6}C + ^{1}<\/em>{0}n}
]<\/p>\n\n\n\n\n
\\ce{^{233}{93}Np -> ^{239}<\/em>{94}Pu + e^{-}}
]<\/p>\n\n\n\n