{"id":160584,"date":"2024-11-03T07:18:53","date_gmt":"2024-11-03T07:18:53","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=160584"},"modified":"2024-11-03T07:18:56","modified_gmt":"2024-11-03T07:18:56","slug":"which-species-is-the-conjugate-acid-of-hco3","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2024\/11\/03\/which-species-is-the-conjugate-acid-of-hco3\/","title":{"rendered":"Which species is the conjugate acid of HCO3-"},"content":{"rendered":"\n<p>Which species is the conjugate acid of HCO3-? <\/p>\n\n\n\n<p>A. CO32- <\/p>\n\n\n\n<p>B. H2CO3 <\/p>\n\n\n\n<p>C. CO2 <\/p>\n\n\n\n<p>D. H2O<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The conjugate acid of ( \\text{HCO}_3^- ) (bicarbonate) is ( \\text{H}_2\\text{CO}_3 ) (carbonic acid). Therefore, the correct answer is <strong>B. ( \\text{H}_2\\text{CO}_3 )<\/strong>.<\/p>\n\n\n\n<p>To understand why ( \\text{H}_2\\text{CO}_3 ) is the conjugate acid of ( \\text{HCO}_3^- ), we must first grasp the concept of conjugate acids and bases within the Br\u00f8nsted-Lowry acid-base theory. In this context, an acid is defined as a proton (H(^+)) donor, while a base is a proton acceptor. When an acid donates a proton, it transforms into its conjugate base; conversely, when a base accepts a proton, it becomes its conjugate acid.<\/p>\n\n\n\n<p>In the case of bicarbonate, ( \\text{HCO}_3^- ) can act as a base. It has the ability to accept a proton (H(^+)) to form carbonic acid ( \\text{H}_2\\text{CO}_3 ). The chemical reaction can be represented as:<\/p>\n\n\n\n<p>[<br>\\text{HCO}_3^- + \\text{H}^+ \\rightarrow \\text{H}_2\\text{CO}_3<br>]<\/p>\n\n\n\n<p>This process illustrates how bicarbonate accepts a proton, thereby becoming its conjugate acid.<\/p>\n\n\n\n<p>Examining the other options:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>A. ( \\text{CO}_3^{2-} )<\/strong> (carbonate) is the conjugate base of ( \\text{HCO}_3^- ), formed when bicarbonate loses a proton.<\/li>\n\n\n\n<li><strong>C. ( \\text{CO}_2 )<\/strong> (carbon dioxide) is not a conjugate acid or base in this context but rather a product formed when carbonic acid dissociates.<\/li>\n\n\n\n<li><strong>D. ( \\text{H}_2\\text{O} )<\/strong> (water) is a neutral molecule and does not relate directly to the conjugate acid-base pair involving bicarbonate.<\/li>\n<\/ul>\n\n\n\n<p>Thus, the relationship between ( \\text{HCO}_3^- ) and ( \\text{H}_2\\text{CO}_3 ) highlights the fundamental principles of acid-base chemistry, with bicarbonate acting as a base that can accept a proton to become carbonic acid, its conjugate acid.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Which species is the conjugate acid of HCO3-? A. CO32- B. H2CO3 C. CO2 D. H2O The Correct Answer and Explanation is: The conjugate acid of ( \\text{HCO}_3^- ) (bicarbonate) is ( \\text{H}_2\\text{CO}_3 ) (carbonic acid). Therefore, the correct answer is B. ( \\text{H}_2\\text{CO}_3 ). To understand why ( \\text{H}_2\\text{CO}_3 ) is the conjugate acid [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-160584","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/160584","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=160584"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/160584\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=160584"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=160584"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=160584"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}