{"id":160863,"date":"2024-11-03T13:48:00","date_gmt":"2024-11-03T13:48:00","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=160863"},"modified":"2024-11-03T13:48:03","modified_gmt":"2024-11-03T13:48:03","slug":"use-greens-theorem-to-evaluate-the-line-integral-along-the-given-positively-oriented-curve","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2024\/11\/03\/use-greens-theorem-to-evaluate-the-line-integral-along-the-given-positively-oriented-curve\/","title":{"rendered":"Use Green&#8217;s Theorem to evaluate the line integral along the given positively oriented curve"},"content":{"rendered":"\n<p>Use Green&#8217;s Theorem to evaluate the line integral along the given positively oriented curve.<br>\u222e<br>C<br>\u200b<br>(ye<br>x<br>dx+2e<br>x<br>dy)<br>C is the rectangle with vertices (0, 0), (3, 0), (3, 2), and (0, 2).<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>To evaluate the line integral<\/p>\n\n\n\n<p>[<br>\\oint_C \\left( y e^x \\, dx + 2 e^x \\, dy \\right)<br>]<\/p>\n\n\n\n<p>using Green&#8217;s Theorem, we first identify the functions involved and set up the theorem correctly. Green&#8217;s Theorem states that if (C) is a positively oriented, simple, closed curve in the plane and (D) is the region bounded by (C), then:<\/p>\n\n\n\n<p>[<br>\\oint_C (P \\, dx + Q \\, dy) = \\iint_D \\left( \\frac{\\partial Q}{\\partial x} &#8211; \\frac{\\partial P}{\\partial y} \\right) dA<br>]<\/p>\n\n\n\n<p>where (P = y e^x) and (Q = 2 e^x).<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Compute the Partial Derivatives<\/h3>\n\n\n\n<p>We need to compute the partial derivatives of (P) and (Q):<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>(P = y e^x)<\/li>\n<\/ul>\n\n\n\n<p>[<br>\\frac{\\partial P}{\\partial y} = e^x<br>]<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>(Q = 2 e^x)<\/li>\n<\/ul>\n\n\n\n<p>[<br>\\frac{\\partial Q}{\\partial x} = 2 e^x<br>]<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Apply Green&#8217;s Theorem<\/h3>\n\n\n\n<p>Now we can substitute these into Green&#8217;s Theorem:<\/p>\n\n\n\n<p>[<br>\\frac{\\partial Q}{\\partial x} &#8211; \\frac{\\partial P}{\\partial y} = 2 e^x &#8211; e^x = e^x<br>]<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Set Up the Double Integral<\/h3>\n\n\n\n<p>Next, we need to evaluate the double integral over the region (D), which is the rectangle with vertices ((0, 0)), ((3, 0)), ((3, 2)), and ((0, 2)):<\/p>\n\n\n\n<p>[<br>\\iint_D e^x \\, dA = \\int_0^3 \\int_0^2 e^x \\, dy \\, dx<br>]<\/p>\n\n\n\n<p>The inner integral with respect to (y) is straightforward:<\/p>\n\n\n\n<p>[<br>\\int_0^2 e^x \\, dy = e^x \\cdot y \\bigg|_0^2 = 2 e^x<br>]<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 4: Evaluate the Outer Integral<\/h3>\n\n\n\n<p>Now we compute the outer integral:<\/p>\n\n\n\n<p>[<br>\\int_0^3 2 e^x \\, dx = 2 \\left( e^x \\bigg|_0^3 \\right) = 2 (e^3 &#8211; e^0) = 2 (e^3 &#8211; 1)<br>]<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Conclusion<\/h3>\n\n\n\n<p>Thus, the value of the line integral is:<\/p>\n\n\n\n<p>[<br>\\oint_C \\left( y e^x \\, dx + 2 e^x \\, dy \\right) = 2 (e^3 &#8211; 1)<br>]<\/p>\n\n\n\n<p>Green&#8217;s Theorem allows us to convert a complex line integral into a more manageable double integral, illustrating the beauty of calculus in connecting line and area calculations.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Use Green&#8217;s Theorem to evaluate the line integral along the given positively oriented curve.\u222eC\u200b(yexdx+2exdy)C is the rectangle with vertices (0, 0), (3, 0), (3, 2), and (0, 2). The Correct Answer and Explanation is : To evaluate the line integral [\\oint_C \\left( y e^x \\, dx + 2 e^x \\, dy \\right)] using Green&#8217;s Theorem, [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-160863","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/160863","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=160863"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/160863\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=160863"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=160863"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=160863"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}