{"id":160997,"date":"2024-11-03T19:55:33","date_gmt":"2024-11-03T19:55:33","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=160997"},"modified":"2024-11-03T19:55:36","modified_gmt":"2024-11-03T19:55:36","slug":"calculate-the-molar-mass-of-bac2h3o22","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2024\/11\/03\/calculate-the-molar-mass-of-bac2h3o22\/","title":{"rendered":"Calculate the molar mass of Ba(C2H3O2)2"},"content":{"rendered":"\n<p>Calculate the molar mass of Ba(C2H3O2)2<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-2-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To calculate the molar mass of barium acetate, represented as Ba(C\u2082H\u2083O\u2082)\u2082, we need to determine the molar mass of each individual atom in the compound and sum them up according to the number of each type of atom present.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Identify the components of barium acetate<\/h3>\n\n\n\n<p>Barium acetate consists of:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>1 Barium (Ba) atom<\/strong><\/li>\n\n\n\n<li><strong>4 Carbon (C) atoms<\/strong> (since there are 2 acetate groups, and each contains 2 carbon atoms)<\/li>\n\n\n\n<li><strong>6 Hydrogen (H) atoms<\/strong> (since there are 2 acetate groups, and each contains 3 hydrogen atoms)<\/li>\n\n\n\n<li><strong>4 Oxygen (O) atoms<\/strong> (since there are 2 acetate groups, and each contains 2 oxygen atoms)<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Determine the molar mass of each element<\/h3>\n\n\n\n<p>Using the periodic table, we find the atomic masses for each element:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Barium (Ba):<\/strong> approximately 137.33 g\/mol<\/li>\n\n\n\n<li><strong>Carbon (C):<\/strong> approximately 12.01 g\/mol<\/li>\n\n\n\n<li><strong>Hydrogen (H):<\/strong> approximately 1.01 g\/mol<\/li>\n\n\n\n<li><strong>Oxygen (O):<\/strong> approximately 16.00 g\/mol<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Calculate the molar mass for each component<\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Barium:<\/strong><br>[<br>1 \\times 137.33 \\, \\text{g\/mol} = 137.33 \\, \\text{g\/mol}<br>]<\/li>\n\n\n\n<li><strong>Carbon:<\/strong><br>[<br>4 \\times 12.01 \\, \\text{g\/mol} = 48.04 \\, \\text{g\/mol}<br>]<\/li>\n\n\n\n<li><strong>Hydrogen:<\/strong><br>[<br>6 \\times 1.01 \\, \\text{g\/mol} = 6.06 \\, \\text{g\/mol}<br>]<\/li>\n\n\n\n<li><strong>Oxygen:<\/strong><br>[<br>4 \\times 16.00 \\, \\text{g\/mol} = 64.00 \\, \\text{g\/mol}<br>]<\/li>\n<\/ol>\n\n\n\n<h3 class=\"wp-block-heading\">Step 4: Sum all contributions<\/h3>\n\n\n\n<p>Now we add all these contributions together to find the total molar mass of Ba(C\u2082H\u2083O\u2082)\u2082:<br>[<br>\\text{Total molar mass} = 137.33 \\, \\text{g\/mol} + 48.04 \\, \\text{g\/mol} + 6.06 \\, \\text{g\/mol} + 64.00 \\, \\text{g\/mol}<br>]<br>[<br>= 255.43 \\, \\text{g\/mol}<br>]<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Conclusion<\/h3>\n\n\n\n<p>The molar mass of barium acetate, Ba(C\u2082H\u2083O\u2082)\u2082, is approximately <strong>255.43 g\/mol<\/strong>. This value is essential in chemistry, particularly when preparing solutions, conducting stoichiometric calculations, and performing quantitative analyses. Understanding molar mass helps chemists convert between grams and moles, enabling more accurate and efficient chemical reactions and analyses.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Calculate the molar mass of Ba(C2H3O2)2 The Correct Answer and Explanation is: To calculate the molar mass of barium acetate, represented as Ba(C\u2082H\u2083O\u2082)\u2082, we need to determine the molar mass of each individual atom in the compound and sum them up according to the number of each type of atom present. Step 1: Identify the [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-160997","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/160997","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=160997"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/160997\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=160997"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=160997"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=160997"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}