What is the molar mass of citric acid (H3C6H5O7)?<\/p>\n\n\n\n
The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n To determine the molar mass of citric acid (chemical formula ( \\text{C}_6\\text{H}_8\\text{O}_7 )), we need to sum the molar masses of all the individual atoms present in the molecule. Citric acid contains carbon (C), hydrogen (H), and oxygen (O) atoms.<\/p>\n\n\n\n Thus, the molar mass of citric acid is approximately 192.14 g\/mol<\/strong>.<\/p>\n\n\n\n The molar mass is crucial in chemistry as it allows for the conversion between grams of a substance and moles, facilitating stoichiometric calculations in reactions. Knowing the molar mass is essential for preparing solutions, conducting titrations, and understanding the quantitative aspects of chemical reactions. Citric acid, being a common organic acid found in citrus fruits, is widely used in food and beverages, as well as in various biochemical processes. Its molar mass plays a key role in calculations involving its concentration in solutions, making it fundamental in both analytical and preparative chemistry.<\/p>\n","protected":false},"excerpt":{"rendered":" What is the molar mass of citric acid (H3C6H5O7)? The Correct Answer and Explanation is: To determine the molar mass of citric acid (chemical formula ( \\text{C}_6\\text{H}_8\\text{O}_7 )), we need to sum the molar masses of all the individual atoms present in the molecule. Citric acid contains carbon (C), hydrogen (H), and oxygen (O) atoms. […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-161735","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/161735","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=161735"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/161735\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=161735"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=161735"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=161735"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}\n
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[
6 \\, \\text{C} \\times 12.01 \\, \\text{g\/mol} = 72.06 \\, \\text{g\/mol}
]<\/li>\n\n\n\n
[
8 \\, \\text{H} \\times 1.01 \\, \\text{g\/mol} = 8.08 \\, \\text{g\/mol}
]<\/li>\n\n\n\n
[
7 \\, \\text{O} \\times 16.00 \\, \\text{g\/mol} = 112.00 \\, \\text{g\/mol}
]<\/li>\n<\/ul>\n\n\n\n\n
Now we add the contributions of each element together to find the total molar mass of citric acid:
[
72.06 \\, \\text{g\/mol} + 8.08 \\, \\text{g\/mol} + 112.00 \\, \\text{g\/mol} = 192.14 \\, \\text{g\/mol}
]<\/li>\n<\/ol>\n\n\n\nImportance of Molar Mass<\/h3>\n\n\n\n