{"id":162674,"date":"2024-11-07T07:34:36","date_gmt":"2024-11-07T07:34:36","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=162674"},"modified":"2024-11-07T07:34:39","modified_gmt":"2024-11-07T07:34:39","slug":"for-each-compound-indicate-the-type-m-molecular-i-ionic-ba-binary-acidoaoxyacid","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2024\/11\/07\/for-each-compound-indicate-the-type-m-molecular-i-ionic-ba-binary-acidoaoxyacid\/","title":{"rendered":"For each compound, indicate the type (M= molecular, I= ionic, BA= binary acid,OA=oxyacid."},"content":{"rendered":"\n<p>For each compound, indicate the type (M= molecular, I= ionic, BA= binary acid,OA=oxyacid. Circle each transition metal. Then name each compound SCl4 , HI , BiN , P4S3, Na202<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>Let&#8217;s go through each compound and identify its type, as well as name it, following the instructions you\u2019ve provided. I will also circle the transition metals and provide a detailed explanation.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">1. <strong>SCl\u2084<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Type:<\/strong> Molecular (M)<\/li>\n\n\n\n<li><strong>Explanation:<\/strong>\n<ul class=\"wp-block-list\">\n<li>This compound is molecular because it consists of two nonmetals: sulfur (S) and chlorine (Cl). Molecular compounds are typically formed between nonmetals, where atoms share electrons. In this case, sulfur forms covalent bonds with four chlorine atoms.<\/li>\n\n\n\n<li><strong>Name:<\/strong> Sulfur tetrachloride.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">2. <strong>HI<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Type:<\/strong> Binary Acid (BA)<\/li>\n\n\n\n<li><strong>Explanation:<\/strong>\n<ul class=\"wp-block-list\">\n<li><strong>HI<\/strong> is a binary acid because it consists of hydrogen (H) and iodine (I), two elements that form a simple binary compound. When dissolved in water, it ionizes to produce H\u207a ions and I\u207b ions, classifying it as an acid.<\/li>\n\n\n\n<li><strong>Name:<\/strong> Hydroiodic acid.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">3. <strong>BiN<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Type:<\/strong> Ionic (I)<\/li>\n\n\n\n<li><strong>Explanation:<\/strong>\n<ul class=\"wp-block-list\">\n<li>This compound is ionic because it consists of a metal, bismuth (Bi), and a nonmetal, nitrogen (N). Ionic compounds are formed when metals transfer electrons to nonmetals. Bismuth, a metal, forms a cation (Bi\u00b3\u207a) while nitrogen forms an anion (N\u00b3\u207b). They bond through electrostatic attraction.<\/li>\n\n\n\n<li><strong>Name:<\/strong> Bismuth nitride.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">4. <strong>P\u2084S\u2083<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Type:<\/strong> Molecular (M)<\/li>\n\n\n\n<li><strong>Explanation:<\/strong>\n<ul class=\"wp-block-list\">\n<li>This is a molecular compound made up of phosphorus (P) and sulfur (S), both nonmetals. Phosphorus and sulfur form covalent bonds with each other, making this compound molecular in nature.<\/li>\n\n\n\n<li><strong>Name:<\/strong> Tetraphosphorus trisulfide.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">5. <strong>Na\u2082O\u2082<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Type:<\/strong> Ionic (I)<\/li>\n\n\n\n<li><strong>Explanation:<\/strong>\n<ul class=\"wp-block-list\">\n<li><strong>Na\u2082O\u2082<\/strong> is an ionic compound. It consists of sodium (Na), a metal, and oxygen (O), a nonmetal. In this compound, sodium exists as Na\u207a ions and oxygen forms peroxide ions (O\u2082\u00b2\u207b). The electrostatic attraction between the cations and anions makes this compound ionic in nature.<\/li>\n\n\n\n<li><strong>Name:<\/strong> Sodium peroxide.<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Summary of the Types:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Molecular Compounds (M):<\/strong><\/li>\n\n\n\n<li>SCl\u2084 (Sulfur tetrachloride)<\/li>\n\n\n\n<li>P\u2084S\u2083 (Tetraphosphorus trisulfide)<\/li>\n\n\n\n<li><strong>Ionic Compounds (I):<\/strong><\/li>\n\n\n\n<li>BiN (Bismuth nitride)<\/li>\n\n\n\n<li>Na\u2082O\u2082 (Sodium peroxide)<\/li>\n\n\n\n<li><strong>Binary Acid (BA):<\/strong><\/li>\n\n\n\n<li>HI (Hydroiodic acid)<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Transition Metals:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Bismuth (Bi)<\/strong> is a transition metal and is <strong>circled<\/strong> in <strong>BiN<\/strong>. Transition metals typically occupy the d-block of the periodic table and are often involved in the formation of ionic compounds.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation of Naming Conventions:<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Molecular compounds<\/strong> are named based on the elements involved, with prefixes indicating the number of atoms (tetra for 4, tri for 3, etc.). Example: &#8220;Sulfur tetrachloride&#8221; for SCl\u2084.<\/li>\n\n\n\n<li><strong>Binary acids<\/strong> are named using the prefix &#8220;hydro-&#8221; followed by the nonmetal&#8217;s name with an &#8220;-ic&#8221; suffix. Example: &#8220;Hydroiodic acid&#8221; for HI.<\/li>\n\n\n\n<li><strong>Ionic compounds<\/strong> follow the naming rule where the metal&#8217;s name is written first, followed by the nonmetal with an &#8220;-ide&#8221; suffix (unless it&#8217;s a polyatomic ion). Example: &#8220;Bismuth nitride&#8221; for BiN.<\/li>\n<\/ul>\n\n\n\n<p>Each compound has a unique naming convention based on its type (molecular, ionic, acid), and these classifications help in understanding their properties and structure.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>For each compound, indicate the type (M= molecular, I= ionic, BA= binary acid,OA=oxyacid. Circle each transition metal. Then name each compound SCl4 , HI , BiN , P4S3, Na202 The Correct Answer and Explanation is: Let&#8217;s go through each compound and identify its type, as well as name it, following the instructions you\u2019ve provided. I [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-162674","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/162674","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=162674"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/162674\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=162674"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=162674"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=162674"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}