{"id":163489,"date":"2024-11-08T20:37:41","date_gmt":"2024-11-08T20:37:41","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=163489"},"modified":"2024-11-08T20:37:44","modified_gmt":"2024-11-08T20:37:44","slug":"which-ionic-equation-represents-a-spontaneous-reaction-that-can-occur-in-a-voltaic-cell","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2024\/11\/08\/which-ionic-equation-represents-a-spontaneous-reaction-that-can-occur-in-a-voltaic-cell\/","title":{"rendered":"Which ionic equation represents a spontaneous reaction that can occur in a voltaic cell"},"content":{"rendered":"\n<p>Which ionic equation represents a spontaneous reaction that can occur in a voltaic cell? 1. Cu(s) + Zn(s) \u2192 Cu2+(aq) + Zn2+(aq) 2. Cu(s) + Zn2+(aq) \u2192 Cu2+(aq) + Zn(s) 3. Cu2+(aq) + Zn(s) \u2192 Cu(s) + Zn2+(aq) 4. Cu2+(aq) + Zn2+(aq) \u2192 Cu(s) + Zn(s)<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The correct answer is <strong>Option 3: Cu\u00b2\u207a(aq) + Zn(s) \u2192 Cu(s) + Zn\u00b2\u207a(aq).<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>In a voltaic (galvanic) cell, a spontaneous redox reaction occurs to produce electrical energy. The reaction involves the transfer of electrons from the anode (where oxidation takes place) to the cathode (where reduction takes place). For a reaction to be spontaneous, it must have a positive cell potential (E\u00b0cell &gt; 0), indicating that the redox reaction releases energy.<\/p>\n\n\n\n<p>Let\u2019s break down each option to understand why Option 3 is correct:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Cu(s) + Zn(s) \u2192 Cu\u00b2\u207a(aq) + Zn\u00b2\u207a(aq)<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>This is a non-spontaneous reaction. If both copper and zinc are solid, it would require external energy (such as a power source) to drive the reaction. This reaction doesn&#8217;t fit the definition of a spontaneous voltaic cell reaction, as it does not involve the movement of electrons that would generate an electric current.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Cu(s) + Zn\u00b2\u207a(aq) \u2192 Cu\u00b2\u207a(aq) + Zn(s)<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>This reaction is also non-spontaneous. In this case, copper is oxidized to Cu\u00b2\u207a, and zinc is reduced. However, zinc would not spontaneously lose electrons to reduce copper. This reaction would need to be forced by external energy.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Cu\u00b2\u207a(aq) + Zn(s) \u2192 Cu(s) + Zn\u00b2\u207a(aq)<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>This is the correct spontaneous redox reaction. Here, zinc metal (Zn) undergoes oxidation at the anode, releasing electrons and turning into Zn\u00b2\u207a. These electrons flow through an external circuit to the cathode, where Cu\u00b2\u207a ions are reduced to copper metal (Cu). This reaction is spontaneous because zinc is more easily oxidized than copper, and the overall cell potential is positive.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Cu\u00b2\u207a(aq) + Zn\u00b2\u207a(aq) \u2192 Cu(s) + Zn(s)<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>This is not a valid voltaic reaction because both Cu\u00b2\u207a and Zn\u00b2\u207a are already in their ionic forms. No solid metals are involved as reactants or products, which makes it non-spontaneous in the context of a voltaic cell.<\/li>\n<\/ul>\n\n\n\n<p>In summary, <strong>Option 3<\/strong> represents the correct spontaneous reaction in a voltaic cell, where zinc metal loses electrons (oxidation), and copper ions gain electrons (reduction), resulting in a flow of electric current.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Which ionic equation represents a spontaneous reaction that can occur in a voltaic cell? 1. Cu(s) + Zn(s) \u2192 Cu2+(aq) + Zn2+(aq) 2. Cu(s) + Zn2+(aq) \u2192 Cu2+(aq) + Zn(s) 3. Cu2+(aq) + Zn(s) \u2192 Cu(s) + Zn2+(aq) 4. Cu2+(aq) + Zn2+(aq) \u2192 Cu(s) + Zn(s) The Correct Answer and Explanation is: The correct answer [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-163489","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/163489","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=163489"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/163489\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=163489"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=163489"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=163489"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}