{"id":163539,"date":"2024-11-08T21:21:50","date_gmt":"2024-11-08T21:21:50","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=163539"},"modified":"2024-11-08T21:21:54","modified_gmt":"2024-11-08T21:21:54","slug":"complete-and-balance-each-of-the-following-equations-for-acid-base-reactions","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2024\/11\/08\/complete-and-balance-each-of-the-following-equations-for-acid-base-reactions\/","title":{"rendered":"Complete and balance each of the following equations for acid-base reactions."},"content":{"rendered":"\n

Complete and balance each of the following equations for acid-base reactions.
HC2H3O2(aq)+NaOH(aq)\u2192<\/p>\n\n\n\n

The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n

The given equation represents the reaction between acetic acid (HC\u2082H\u2083O\u2082) and sodium hydroxide (NaOH), which is an acid-base neutralization reaction. Here’s the balanced equation:<\/p>\n\n\n\n

Unbalanced equation:<\/strong>
[ \\text{HC}_2\\text{H}_3\\text{O}_2(aq) + \\text{NaOH}(aq) \\rightarrow ]<\/p>\n\n\n\n

Balanced equation:<\/strong>
[ \\text{HC}_2\\text{H}_3\\text{O}_2(aq) + \\text{NaOH}(aq) \\rightarrow \\text{NaC}_2\\text{H}_3\\text{O}_2(aq) + \\text{H}_2\\text{O}(l) ]<\/p>\n\n\n\n

Explanation:<\/h3>\n\n\n\n
    \n
  1. Identifying the Acid and Base:<\/strong><\/li>\n<\/ol>\n\n\n\n
      \n
    • Acetic acid (HC\u2082H\u2083O\u2082)<\/strong> is the acid. It donates a proton (H\u207a) in the reaction.<\/li>\n\n\n\n
    • Sodium hydroxide (NaOH)<\/strong> is the base. It dissociates in water to form hydroxide ions (OH\u207b), which accept a proton.<\/li>\n<\/ul>\n\n\n\n
        \n
      1. Reaction Mechanism:<\/strong>
        In an acid-base neutralization reaction, the proton (H\u207a) from the acid reacts with the hydroxide ion (OH\u207b) from the base to form water (H\u2082O). The remaining components form a salt. In this case, acetic acid (HC\u2082H\u2083O\u2082) donates a proton to the hydroxide ion, resulting in water, while the sodium ion (Na\u207a) combines with the acetate ion (C\u2082H\u2083O\u2082\u207b) to form sodium acetate (NaC\u2082H\u2083O\u2082), the salt produced in this reaction.<\/li>\n\n\n\n
      2. Balanced Chemical Equation:<\/strong><\/li>\n<\/ol>\n\n\n\n
          \n
        • On the left side, we have one molecule of acetic acid (HC\u2082H\u2083O\u2082) and one molecule of sodium hydroxide (NaOH).<\/li>\n\n\n\n
        • On the right side, we have the products of the reaction: sodium acetate (NaC\u2082H\u2083O\u2082) and water (H\u2082O).<\/li>\n\n\n\n
        • Both the atoms and charges are balanced. The sodium (Na\u207a) from NaOH pairs with the acetate ion (C\u2082H\u2083O\u2082\u207b) from acetic acid, and the hydroxide ion (OH\u207b) from NaOH combines with the proton (H\u207a) from acetic acid to form water.<\/li>\n<\/ul>\n\n\n\n
            \n
          1. Ionization in Solution:<\/strong>
            When acetic acid and sodium hydroxide are dissolved in water, they dissociate into ions:<\/li>\n<\/ol>\n\n\n\n
              \n
            • Acetic acid<\/strong> dissociates as: (\\text{HC}_2\\text{H}_3\\text{O}_2 \\rightleftharpoons \\text{H}^+ + \\text{C}_2\\text{H}_3\\text{O}_2^-)<\/li>\n\n\n\n
            • Sodium hydroxide<\/strong> dissociates completely as: (\\text{NaOH} \\rightarrow \\text{Na}^+ + \\text{OH}^-)<\/li>\n<\/ul>\n\n\n\n
                \n
              1. Overall Reaction:<\/strong>
                The reaction is essentially the combination of the proton ((\\text{H}^+)) from the acetic acid with the hydroxide ion ((\\text{OH}^-)) from sodium hydroxide to form water, and the remaining ions form the salt.<\/li>\n<\/ol>\n\n\n\n

                The complete and balanced equation for the neutralization is:<\/p>\n\n\n\n

                [
                \\text{HC}_2\\text{H}_3\\text{O}_2(aq) + \\text{NaOH}(aq) \\rightarrow \\text{NaC}_2\\text{H}_3\\text{O}_2(aq) + \\text{H}_2\\text{O}(l)
                ]<\/p>\n\n\n\n

                This represents a typical acid-base neutralization, where an acid reacts with a base to form a salt and water.<\/p>\n","protected":false},"excerpt":{"rendered":"

                Complete and balance each of the following equations for acid-base reactions.HC2H3O2(aq)+NaOH(aq)\u2192 The Correct Answer and Explanation is: The given equation represents the reaction between acetic acid (HC\u2082H\u2083O\u2082) and sodium hydroxide (NaOH), which is an acid-base neutralization reaction. Here’s the balanced equation: Unbalanced equation:[ \\text{HC}_2\\text{H}_3\\text{O}_2(aq) + \\text{NaOH}(aq) \\rightarrow ] Balanced equation:[ \\text{HC}_2\\text{H}_3\\text{O}_2(aq) + \\text{NaOH}(aq) \\rightarrow \\text{NaC}_2\\text{H}_3\\text{O}_2(aq) […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-163539","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/163539","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=163539"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/163539\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=163539"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=163539"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=163539"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}