{"id":164157,"date":"2024-11-09T13:59:21","date_gmt":"2024-11-09T13:59:21","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=164157"},"modified":"2024-11-09T13:59:24","modified_gmt":"2024-11-09T13:59:24","slug":"solve-for-x","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2024\/11\/09\/solve-for-x\/","title":{"rendered":"Solve for x"},"content":{"rendered":"\n<p>Solve for x. x + 5 = 2x<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>To solve the equation ( x + 5 = 2x ), follow these steps:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Understand the equation<\/h3>\n\n\n\n<p>The equation is a simple linear equation involving the variable ( x ). We need to isolate ( x ) on one side of the equation to find its value.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Subtract ( x ) from both sides<\/h3>\n\n\n\n<p>We want to get all terms involving ( x ) on one side of the equation. To do this, subtract ( x ) from both sides:<\/p>\n\n\n\n<p>[<br>x + 5 &#8211; x = 2x &#8211; x<br>]<\/p>\n\n\n\n<p>Simplifying both sides:<\/p>\n\n\n\n<p>[<br>5 = x<br>]<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Interpret the result<\/h3>\n\n\n\n<p>After simplifying the equation, we see that ( x = 5 ). This is the solution to the equation.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 4: Verify the solution<\/h3>\n\n\n\n<p>To verify that our solution is correct, substitute ( x = 5 ) back into the original equation:<\/p>\n\n\n\n<p>[<br>x + 5 = 2x<br>]<\/p>\n\n\n\n<p>Substituting ( x = 5 ):<\/p>\n\n\n\n<p>[<br>5 + 5 = 2(5)<br>]<\/p>\n\n\n\n<p>[<br>10 = 10<br>]<\/p>\n\n\n\n<p>Since both sides are equal, the solution ( x = 5 ) is correct.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation of the process<\/h3>\n\n\n\n<p>In solving this equation, we used basic algebraic principles. The goal in any linear equation is to isolate the variable (in this case, ( x )) on one side of the equation. By subtracting ( x ) from both sides, we eliminated the variable on the left side, allowing us to find the value of ( x ).<\/p>\n\n\n\n<p>This type of equation is commonly encountered in algebra and is important for solving more complex equations and systems of equations. It illustrates the fundamental principle of maintaining equality: whatever operation you perform on one side of the equation must also be performed on the other side.<\/p>\n\n\n\n<p>In summary, the solution to the equation ( x + 5 = 2x ) is ( x = 5 ). This result was verified by substituting it back into the original equation to ensure the sides remain balanced.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Solve for x. x + 5 = 2x The Correct Answer and Explanation is : To solve the equation ( x + 5 = 2x ), follow these steps: Step 1: Understand the equation The equation is a simple linear equation involving the variable ( x ). We need to isolate ( x ) on [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-164157","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/164157","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=164157"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/164157\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=164157"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=164157"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=164157"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}