how many grams of solute will be left if a saturated solution of NaNO3 in 50 grams of water at 30 degrees celsius is completely evaporated to dryness?<\/p>\n\n\n\n
The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n To solve this, we need to determine how many grams of NaNO\u2083 (sodium nitrate) will remain in the solution after the water has evaporated. This can be done by first finding the solubility of NaNO\u2083 in water at 30\u00b0C, and then applying that information to the 50 grams of water in the solution.<\/p>\n\n\n\n The solubility of NaNO\u2083 in water at 30\u00b0C is approximately 92 grams of NaNO\u2083 per 100 grams of water<\/strong>.<\/p>\n\n\n\n Since the solubility is 92 grams per 100 grams of water, we can set up a proportion to find how many grams of NaNO\u2083 can dissolve in 50 grams of water:<\/p>\n\n\n\n [ Solving for (x):<\/p>\n\n\n\n [ When the water is completely evaporated, the dissolved NaNO\u2083 will be left behind as solid crystals. Since the solubility at 30\u00b0C is 46 grams of NaNO\u2083 in 50 grams of water, and the solution is saturated, all 46 grams of NaNO\u2083 will remain after the evaporation process.<\/p>\n\n\n\n After the solution is evaporated to dryness, 46 grams of NaNO\u2083<\/strong> will remain as the solute.<\/p>\n\n\n\n Solubility refers to the maximum amount of solute that can dissolve in a given amount of solvent at a specific temperature. At 30\u00b0C, 92 grams of NaNO\u2083 can dissolve in 100 grams of water, meaning a saturated solution at that temperature would contain this maximum amount of solute. Since the solution is saturated, we know that 46 grams of NaNO\u2083 will dissolve in 50 grams of water. Upon evaporation, all 46 grams of NaNO\u2083 will be left behind as the water (solvent) evaporates completely, leaving the solute behind as solid NaNO\u2083.<\/p>\n","protected":false},"excerpt":{"rendered":" how many grams of solute will be left if a saturated solution of NaNO3 in 50 grams of water at 30 degrees celsius is completely evaporated to dryness? The Correct Answer and Explanation is : To solve this, we need to determine how many grams of NaNO\u2083 (sodium nitrate) will remain in the solution after […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-164283","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/164283","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=164283"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/164283\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=164283"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=164283"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=164283"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}Step 1: Find the solubility of NaNO\u2083 at 30\u00b0C<\/h3>\n\n\n\n
Step 2: Determine how much NaNO\u2083 can dissolve in 50 grams of water<\/h3>\n\n\n\n
\\frac{92 \\text{ g NaNO\u2083}}{100 \\text{ g H\u2082O}} = \\frac{x \\text{ g NaNO\u2083}}{50 \\text{ g H\u2082O}}
]<\/p>\n\n\n\n
x = \\frac{92 \\times 50}{100} = 46 \\text{ g NaNO\u2083}
]<\/p>\n\n\n\nStep 3: Evaporation process<\/h3>\n\n\n\n
Final Answer:<\/h3>\n\n\n\n
Explanation:<\/h3>\n\n\n\n