What is the net ionic equation of 2h+ + so42- + ca2+ + 2i- caso4 + 2h+ + 2i-?<\/p>\n\n\n\n
The Correct Answer and Explanation is:<\/strong><\/mark><\/p>\n\n\n\n The given equation is:<\/p>\n\n\n\n [ 2H^+ + SO_4^{2-} + Ca^{2+} + 2I^- \\rightarrow CaSO_4 + 2H^+ + 2I^- ]<\/p>\n\n\n\n To find the net ionic equation, we need to eliminate the spectator ions\u2014those that remain unchanged on both sides of the equation\u2014and focus only on the species that undergo chemical change.<\/p>\n\n\n\n This is the complete ionic equation as written:<\/p>\n\n\n\n [ 2H^+ (aq) + SO_4^{2-} (aq) + Ca^{2+} (aq) + 2I^- (aq) \\rightarrow CaSO_4 (s) + 2H^+ (aq) + 2I^- (aq) ]<\/p>\n\n\n\n Spectator ions are ions that appear on both sides of the equation in the same form. In this case, we see that ( 2H^+ ) and ( 2I^- ) appear on both the left and right sides of the equation, so they do not participate in the reaction and are considered spectator ions.<\/p>\n\n\n\n We remove the spectator ions from both sides of the equation:<\/p>\n\n\n\n [ SO_4^{2-} (aq) + Ca^{2+} (aq) \\rightarrow CaSO_4 (s) ]<\/p>\n\n\n\n After removing the spectator ions, the net ionic equation is:<\/p>\n\n\n\n [ Ca^{2+} (aq) + SO_4^{2-} (aq) \\rightarrow CaSO_4 (s) ]<\/p>\n\n\n\n This reaction represents the precipitation of calcium sulfate (( CaSO_4 )) from its ions in solution. Calcium ions (( Ca^{2+} )) and sulfate ions (( SO_4^{2-} )) combine to form solid calcium sulfate, which precipitates out of the solution. The ( H^+ ) and ( I^- ) ions do not participate in the formation of the precipitate and remain unchanged throughout the reaction, hence they are spectator ions.<\/p>\n\n\n\n This type of reaction is a double displacement or precipitation reaction, where two soluble ionic compounds in solution react to form an insoluble product (precipitate). In this case, ( CaSO_4 ) is the precipitate.<\/p>\n","protected":false},"excerpt":{"rendered":" What is the net ionic equation of 2h+ + so42- + ca2+ + 2i- caso4 + 2h+ + 2i-? The Correct Answer and Explanation is: The given equation is: [ 2H^+ + SO_4^{2-} + Ca^{2+} + 2I^- \\rightarrow CaSO_4 + 2H^+ + 2I^- ] To find the net ionic equation, we need to eliminate the […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-164695","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/164695","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=164695"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/164695\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=164695"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=164695"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=164695"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}Step 1: Identify the complete ionic equation<\/h3>\n\n\n\n
Step 2: Identify the spectator ions<\/h3>\n\n\n\n
Step 3: Remove the spectator ions<\/h3>\n\n\n\n
Step 4: Final Net Ionic Equation<\/h3>\n\n\n\n
Explanation:<\/h3>\n\n\n\n