What is the molar mass of AlBr3<\/p>\n\n\n\n
The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n The molar mass of aluminum bromide (AlBr\u2083) is calculated by adding the molar masses of its constituent elements, aluminum (Al) and bromine (Br).<\/p>\n\n\n\n Thus, the molar mass of AlBr\u2083 is 266.68 g\/mol<\/strong>.<\/p>\n\n\n\n The molar mass is the mass of one mole of a substance, which is equivalent to the molecular weight expressed in grams. The molecular weight corresponds to the sum of the atomic masses of all the atoms in a molecule. In the case of AlBr\u2083, it consists of one aluminum atom and three bromine atoms. The atomic mass of each element can be found on the periodic table, and multiplying the atomic mass of bromine by three reflects the fact that there are three bromine atoms in each AlBr\u2083 unit. By summing these values, we determine the total molar mass. This value is crucial in stoichiometric calculations for reactions involving AlBr\u2083, such as determining the amount of AlBr\u2083 required or produced in chemical reactions.<\/p>\n","protected":false},"excerpt":{"rendered":" What is the molar mass of AlBr3 The Correct Answer and Explanation is : The molar mass of aluminum bromide (AlBr\u2083) is calculated by adding the molar masses of its constituent elements, aluminum (Al) and bromine (Br). Step-by-step Calculation: Thus, the molar mass of AlBr\u2083 is 266.68 g\/mol. Explanation: The molar mass is the mass […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-164803","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/164803","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=164803"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/164803\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=164803"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=164803"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=164803"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}Step-by-step Calculation:<\/h3>\n\n\n\n
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[
3 \\times 79.90 \\, \\text{g\/mol} = 239.70 \\, \\text{g\/mol}
]<\/li>\n<\/ul>\n\n\n\n\n
To find the total molar mass of AlBr\u2083, add the molar mass of aluminum to the total molar mass of the bromine atoms:
[
26.98 \\, \\text{g\/mol} + 239.70 \\, \\text{g\/mol} = 266.68 \\, \\text{g\/mol}
]<\/li>\n<\/ol>\n\n\n\nExplanation:<\/h3>\n\n\n\n