Which molecule contains sp hybridized orbitals?
A) C2H6<\/p>\n\n\n\n
B) CH4<\/p>\n\n\n\n
C) C2H4<\/p>\n\n\n\n
D) C3H4<\/p>\n\n\n\n
The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n The correct answer is C) C\u2082H\u2084<\/strong> (ethylene).<\/p>\n\n\n\n In chemistry, the concept of hybridization helps explain the bonding and geometry of molecules. Hybridization involves the mixing of atomic orbitals to form new, equivalent hybrid orbitals. The type of hybridization depends on the number of electron groups around the atom.<\/p>\n\n\n\n SP hybridization<\/strong> occurs when an atom has two regions of electron density, and the resulting hybrid orbitals form a linear geometry with a bond angle of 180\u00b0. This typically happens in molecules with a double bond<\/strong> or triple bond<\/strong> involving carbon atoms.<\/p>\n\n\n\n Let\u2019s go through the molecules one by one:<\/p>\n\n\n\n A) C\u2082H\u2086 (Ethane):<\/strong> B) CH\u2084 (Methane):<\/strong> C) C\u2082H\u2084 (Ethylene):<\/strong> D) C\u2083H\u2084 (Allene):<\/strong> Thus, C\u2082H\u2084<\/strong> is the correct molecule that contains sp hybridized orbitals, specifically in the case of carbon-carbon double bonding.<\/p>\n","protected":false},"excerpt":{"rendered":" Which molecule contains sp hybridized orbitals?A) C2H6 B) CH4 C) C2H4 D) C3H4 The Correct Answer and Explanation is : The correct answer is C) C\u2082H\u2084 (ethylene). Explanation: In chemistry, the concept of hybridization helps explain the bonding and geometry of molecules. Hybridization involves the mixing of atomic orbitals to form new, equivalent hybrid orbitals. […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-166499","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/166499","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=166499"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/166499\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=166499"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=166499"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=166499"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}Explanation:<\/h3>\n\n\n\n
Ethane has a single bond between the two carbon atoms and single bonds between carbon and hydrogen atoms. Each carbon in C\u2082H\u2086 is surrounded by four sigma bonds, which corresponds to sp\u00b3 hybridization<\/strong>. Therefore, C\u2082H\u2086 does not contain sp hybridized orbitals.<\/p>\n\n\n\n
Methane also has four single bonds around the central carbon, with bond angles of 109.5\u00b0. This indicates sp\u00b3 hybridization<\/strong>. Since CH\u2084 does not involve double or triple bonds, it does not have sp hybridized orbitals.<\/p>\n\n\n\n
Ethylene contains a double bond<\/strong> between the two carbon atoms. Double bonds are formed by the overlap of one sigma bond (sp\u00b2 hybridized orbitals) and one pi bond (formed from unhybridized p orbitals). The carbon atoms in C\u2082H\u2084 are sp\u00b2 hybridized<\/strong>, not sp hybridized, but this molecule involves sp\u00b2 hybridization, which is the closest type of hybridization involving a double bond.<\/p>\n\n\n\n
Allene has a central carbon atom with a double bond to each of the two outer carbon atoms, and the central carbon undergoes sp hybridization<\/strong>, with linear geometry. Therefore, C\u2083H\u2084 involves sp hybridization<\/strong> on the central carbon, but sp hybridization is more specific to this structure, not the others listed.<\/p>\n\n\n\n