In which of the following processes will \u0394S\u00b0 be negative?<\/p>\n\n\n\n
a) C2H5OH(l)\u2192C2H5OH(g)<\/p>\n\n\n\n
b) NaCl(s)\u2192NaCl(l)<\/p>\n\n\n\n
c) CO2(s)\u2192CO2(g)<\/p>\n\n\n\n
d) Cl2(g)\u2192Cl2(l)<\/p>\n\n\n\n
The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n The correct answer is d) Cl\u2082(g) \u2192 Cl\u2082(l)<\/strong>.<\/p>\n\n\n\n Entropy (\u0394S\u00b0) is a thermodynamic property that measures the disorder or randomness of a system. A negative \u0394S\u00b0 indicates a decrease in entropy, meaning the system is becoming more ordered. Conversely, a positive \u0394S\u00b0 indicates an increase in entropy, which corresponds to greater randomness.<\/p>\n\n\n\n Let’s analyze each of the options:<\/p>\n\n\n\n a) C\u2082H\u2085OH(l) \u2192 C\u2082H\u2085OH(g):<\/strong> b) NaCl(s) \u2192 NaCl(l):<\/strong> c) CO\u2082(s) \u2192 CO\u2082(g):<\/strong> d) Cl\u2082(g) \u2192 Cl\u2082(l):<\/strong> Thus, the correct answer is d) Cl\u2082(g) \u2192 Cl\u2082(l)<\/strong>, where the process involves a reduction in entropy, as the gas phase becomes more ordered in the liquid phase.<\/p>\n","protected":false},"excerpt":{"rendered":" In which of the following processes will \u0394S\u00b0 be negative? a) C2H5OH(l)\u2192C2H5OH(g) b) NaCl(s)\u2192NaCl(l) c) CO2(s)\u2192CO2(g) d) Cl2(g)\u2192Cl2(l) The Correct Answer and Explanation is: The correct answer is d) Cl\u2082(g) \u2192 Cl\u2082(l). Explanation: Entropy (\u0394S\u00b0) is a thermodynamic property that measures the disorder or randomness of a system. A negative \u0394S\u00b0 indicates a decrease in […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-168035","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/168035","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=168035"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/168035\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=168035"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=168035"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=168035"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}Explanation:<\/h3>\n\n\n\n
This process involves the vaporization of ethanol from a liquid state to a gas. When a substance transitions from liquid to gas, the molecules are moving from a more ordered state (liquid) to a more disordered state (gas). Therefore, this transition increases entropy, resulting in a positive \u0394S\u00b0. Hence, this option does not represent a process with negative \u0394S\u00b0.<\/p>\n\n\n\n
This is the melting of sodium chloride (NaCl) from a solid to a liquid. In the solid state, NaCl molecules are closely packed in a highly ordered lattice structure. Upon melting, the molecules gain more freedom of movement in the liquid phase, leading to an increase in entropy. Therefore, this transition has a positive \u0394S\u00b0, not a negative one.<\/p>\n\n\n\n
This is the sublimation of carbon dioxide (CO\u2082) from a solid to a gas. In the solid state, CO\u2082 molecules are arranged in a rigid, ordered structure. As it transitions to a gas, the molecules spread out and move more freely, increasing the disorder. This process also results in a positive \u0394S\u00b0, indicating an increase in entropy.<\/p>\n\n\n\n
This process represents the condensation of chlorine gas into a liquid. As chlorine gas condenses, the molecules move from a highly disordered state (gas) to a more ordered state (liquid), which decreases entropy. Therefore, this transition corresponds to a negative \u0394S\u00b0 because the system becomes more ordered as the gas molecules lose their freedom of movement and organize into a liquid state.<\/p>\n\n\n\n