{"id":168282,"date":"2024-11-17T06:36:42","date_gmt":"2024-11-17T06:36:42","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=168282"},"modified":"2024-11-17T06:37:14","modified_gmt":"2024-11-17T06:37:14","slug":"a-tablet-draws-10-0-a-when-plugged-into-a-150-v-line","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2024\/11\/17\/a-tablet-draws-10-0-a-when-plugged-into-a-150-v-line\/","title":{"rendered":"A tablet draws 10.0 A when plugged into a 150-V line."},"content":{"rendered":"\n<p>A tablet draws 10.0 A when plugged into a 150-V line. If another tablet has twice as much resistance, what would the current of the second tablet be if plugged into the same line?<br>0.60 A<br>1.5 A<br>5 A<br>15 A<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To solve this problem, we need to use <strong>Ohm&#8217;s Law<\/strong>:I=VRI = \\frac{V}{R}I=RV\u200b<\/p>\n\n\n\n<p>Where:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>III is the current (in amperes, A)<\/li>\n\n\n\n<li>VVV is the voltage (in volts, V)<\/li>\n\n\n\n<li>RRR is the resistance (in ohms, \u03a9\\Omega\u03a9)<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Determine the resistance of the first tablet<\/h3>\n\n\n\n<p>The first tablet draws 10.0 A of current when connected to a 150-V line. Using Ohm\u2019s Law:R1=VI=150\u2009V10.0\u2009A=15\u2009\u03a9R_1 = \\frac{V}{I} = \\frac{150 \\, \\text{V}}{10.0 \\, \\text{A}} = 15 \\, \\OmegaR1\u200b=IV\u200b=10.0A150V\u200b=15\u03a9<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Find the resistance of the second tablet<\/h3>\n\n\n\n<p>The second tablet has <strong>twice as much resistance<\/strong> as the first tablet. Therefore:R2=2\u00d7R1=2\u00d715\u2009\u03a9=30\u2009\u03a9R_2 = 2 \\times R_1 = 2 \\times 15 \\, \\Omega = 30 \\, \\OmegaR2\u200b=2\u00d7R1\u200b=2\u00d715\u03a9=30\u03a9<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Calculate the current for the second tablet<\/h3>\n\n\n\n<p>The voltage remains the same (150 V), so the current I2I_2I2\u200b for the second tablet is:I2=VR2=150\u2009V30\u2009\u03a9=5.0\u2009AI_2 = \\frac{V}{R_2} = \\frac{150 \\, \\text{V}}{30 \\, \\Omega} = 5.0 \\, \\text{A}I2\u200b=R2\u200bV\u200b=30\u03a9150V\u200b=5.0A<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Final Answer:<\/h3>\n\n\n\n<p>The current for the second tablet is <strong>5 A<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>This question demonstrates the relationship between resistance and current for a fixed voltage. When resistance increases, current decreases proportionally because they are inversely related in Ohm&#8217;s Law. Doubling the resistance (2\u00d715\u2009\u03a9=30\u2009\u03a92 \\times 15 \\, \\Omega = 30 \\, \\Omega2\u00d715\u03a9=30\u03a9) reduces the current by half since the voltage (150\u2009V150 \\, \\text{V}150V) stays constant.<\/p>\n\n\n\n<p>In the first case, a resistance of 15\u2009\u03a915 \\, \\Omega15\u03a9 allowed 10\u2009A10 \\, \\text{A}10A of current to flow. With twice the resistance (30\u2009\u03a930 \\, \\Omega30\u03a9), the current decreases to 5\u2009A5 \\, \\text{A}5A. This reflects the principle that electrical devices with higher resistance draw less current when connected to the same voltage source.<\/p>\n\n\n\n<p>The correct answer is <strong>5 A<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>A tablet draws 10.0 A when plugged into a 150-V line. If another tablet has twice as much resistance, what would the current of the second tablet be if plugged into the same line?0.60 A1.5 A5 A15 A The Correct Answer and Explanation is: To solve this problem, we need to use Ohm&#8217;s Law:I=VRI = [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-168282","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/168282","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=168282"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/168282\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=168282"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=168282"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=168282"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}