If one of the reactants in a reaction is Na20, what is known about the products?
A. The products will have no more than 2 Na atoms and 1 0 atom.
B. There is not enough information to say anything about the products.
C. The products will contain exactly 2 Na atoms and 1 O atom.
D. The products will have at least 2 Na atoms and 1 0 atom.\u200b<\/p>\n\n\n\n
The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n The correct answer is D. The products will have at least 2 Na atoms and 1 O atom.<\/strong><\/p>\n\n\n\n The reactant in the given question is sodium oxide, ( \\text{Na}_2\\text{O} ), which is a compound composed of sodium (Na) and oxygen (O). When sodium oxide (( \\text{Na}_2\\text{O} )) reacts in a chemical reaction, it typically interacts with other substances, often forming new products by bonding with other elements.<\/p>\n\n\n\n The key point here is that sodium oxide is a binary compound consisting of 2 sodium (Na) atoms and 1 oxygen (O) atom. The reaction type and products depend on what sodium oxide reacts with. For instance, if sodium oxide reacts with water (( \\text{H}_2\\text{O} )), it forms sodium hydroxide (( \\text{NaOH} )):<\/p>\n\n\n\n [ In this case, the products are sodium hydroxide molecules, each of which contains one sodium atom and one hydroxide group (( \\text{OH} )). This type of reaction, where sodium oxide reacts with water, leads to the formation of products that still contain the 2 sodium atoms and 1 oxygen atom from the original reactant, albeit rearranged into different molecular structures.<\/p>\n\n\n\n In other cases, sodium oxide can react with acids, forming salts. For example, reacting sodium oxide with sulfuric acid (( \\text{H}_2\\text{SO}_4 )) would produce sodium sulfate (( \\text{Na}_2\\text{SO}_4 )):<\/p>\n\n\n\n [ In this example, the 2 sodium atoms and 1 oxygen atom from sodium oxide combine with other elements, and the products still contain at least 2 sodium atoms and 1 oxygen atom, as required by the conservation of mass.<\/p>\n\n\n\n Thus, while the specific molecular structure of the products depends on the other reactants, it is guaranteed that at least 2 sodium atoms and 1 oxygen atom will be present<\/strong> in the products because of the composition of the sodium oxide reactant. Therefore, answer choice D is the most accurate.<\/p>\n","protected":false},"excerpt":{"rendered":" If one of the reactants in a reaction is Na20, what is known about the products?A. The products will have no more than 2 Na atoms and 1 0 atom.B. There is not enough information to say anything about the products.C. The products will contain exactly 2 Na atoms and 1 O atom.D. The products […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-168467","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/168467","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=168467"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/168467\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=168467"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=168467"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=168467"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}Explanation:<\/h3>\n\n\n\n
\\text{Na}_2\\text{O} + \\text{H}_2\\text{O} \\rightarrow 2 \\text{NaOH}
]<\/p>\n\n\n\n
\\text{Na}_2\\text{O} + \\text{H}_2\\text{SO}_4 \\rightarrow \\text{Na}_2\\text{SO}_4 + \\text{H}_2\\text{O}
]<\/p>\n\n\n\n