{"id":168634,"date":"2024-11-17T19:42:04","date_gmt":"2024-11-17T19:42:04","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=168634"},"modified":"2024-11-17T19:42:06","modified_gmt":"2024-11-17T19:42:06","slug":"for-each-of-the-following-compounds-circle-all-stereocenters","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2024\/11\/17\/for-each-of-the-following-compounds-circle-all-stereocenters\/","title":{"rendered":"For each of the following compounds, circle all stereocenters."},"content":{"rendered":"\n<p>For each of the following compounds, circle all stereocenters. If there are no stereocenters in the compound, circle &#8220;no stereocenters.&#8221;<br>a) CH\u2083CHClBr<br>b) H\u2082C=CH-CH\u2082-CHO<br>c) C\u2086H\u20812O\u2086<br>d) C\u2084H\u20810<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To determine stereocenters, we must understand the concept: a stereocenter (or chiral center) is typically a carbon atom bonded to four different groups. Such carbons create non-superimposable mirror images (enantiomers). Here is the analysis for each compound:<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>a) CH\u2083CHClBr<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The central carbon (CH) is bonded to four different groups:<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li>Hydrogen (H)<\/li>\n\n\n\n<li>Methyl group (CH\u2083)<\/li>\n\n\n\n<li>Chlorine (Cl)<\/li>\n\n\n\n<li>Bromine (Br)<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Since all substituents are unique, this central carbon is a stereocenter.<\/li>\n<\/ul>\n\n\n\n<p><strong>Answer<\/strong>: One stereocenter (CH).<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>b) H\u2082C=CH-CH\u2082-CHO<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>No carbon in this structure satisfies the stereocenter criteria:<\/li>\n\n\n\n<li>The first carbon (H\u2082C=) is part of a double bond and does not have four different groups.<\/li>\n\n\n\n<li>The second carbon (CH=) is also part of the double bond, so it is not a stereocenter.<\/li>\n\n\n\n<li>The third carbon (CH\u2082-) is bonded to two hydrogens, disqualifying it.<\/li>\n\n\n\n<li>The aldehyde carbon (CHO) is double-bonded to oxygen and hence not a stereocenter.<\/li>\n<\/ul>\n\n\n\n<p><strong>Answer<\/strong>: No stereocenters.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>c) C\u2086H\u2081\u2082O\u2086 (Glucose)<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>In glucose, several carbons meet the stereocenter criteria:<\/li>\n\n\n\n<li>Each carbon in the chain, except C1 (aldehyde) and C6 (CH\u2082OH), is attached to four different groups.<\/li>\n\n\n\n<li>The stereocenters are at C2, C3, C4, and C5.<\/li>\n<\/ul>\n\n\n\n<p><strong>Answer<\/strong>: Four stereocenters (C2, C3, C4, C5).<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>d) C\u2084H\u2081\u2080 (Butane or Isobutane)<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>For linear butane, none of the carbons have four different groups:<\/li>\n\n\n\n<li>The terminal carbons are CH\u2083 (three hydrogens).<\/li>\n\n\n\n<li>The inner carbons are CH\u2082 (two hydrogens).<\/li>\n\n\n\n<li>For isobutane (branched), all carbons are bonded to duplicate groups (e.g., two CH\u2083).<\/li>\n<\/ul>\n\n\n\n<p><strong>Answer<\/strong>: No stereocenters.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation Summary (300 Words)<\/h3>\n\n\n\n<p>A stereocenter is a carbon atom attached to four different substituents, giving rise to chirality. Chirality is key in stereoisomerism, critical in biochemistry and pharmacology. In <strong>CH\u2083CHClBr<\/strong>, the central carbon&#8217;s unique substituents make it a stereocenter, leading to two possible enantiomers. Conversely, <strong>H\u2082C=CH-CH\u2082-CHO<\/strong> has no stereocenters since no carbon has four distinct groups; double bonds or duplicate substituents prevent chirality. In <strong>C\u2086H\u2081\u2082O\u2086 (glucose)<\/strong>, stereocenters are common due to multiple asymmetric carbons in the structure, enabling glucose&#8217;s various stereoisomers. Lastly, <strong>C\u2084H\u2081\u2080 (butane and isobutane)<\/strong> lacks stereocenters due to symmetrical and repeated substituents. Understanding these principles helps clarify molecular chirality in chemical and biological systems.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>For each of the following compounds, circle all stereocenters. If there are no stereocenters in the compound, circle &#8220;no stereocenters.&#8221;a) CH\u2083CHClBrb) H\u2082C=CH-CH\u2082-CHOc) C\u2086H\u20812O\u2086d) C\u2084H\u20810 The Correct Answer and Explanation is: To determine stereocenters, we must understand the concept: a stereocenter (or chiral center) is typically a carbon atom bonded to four different groups. Such carbons [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-168634","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/168634","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=168634"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/168634\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=168634"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=168634"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=168634"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}