{"id":169629,"date":"2024-11-19T12:21:01","date_gmt":"2024-11-19T12:21:01","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=169629"},"modified":"2024-11-19T12:21:03","modified_gmt":"2024-11-19T12:21:03","slug":"what-is-the-conjugate-base-of-hso3%e2%88%92","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2024\/11\/19\/what-is-the-conjugate-base-of-hso3%e2%88%92\/","title":{"rendered":"What is the conjugate base of hso3\u2212"},"content":{"rendered":"\n<p>What is the conjugate base of hso3\u2212? express your answer as a chemical formula.<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\">The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The conjugate base of the bisulfite ion ((\\text{HSO}_3^-)) is the sulfite ion, (\\text{SO}_3^{2-}).<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>In acid-base chemistry, a conjugate base is the species that remains after an acid has donated a proton (H\u207a). In this case, the bisulfite ion ((\\text{HSO}_3^-)) can act as an acid, which means it has the potential to donate a proton to another molecule.<\/p>\n\n\n\n<p>To understand this, consider the dissociation of bisulfite:<\/p>\n\n\n\n<p>[<br>\\text{HSO}_3^- \\rightleftharpoons \\text{H}^+ + \\text{SO}_3^{2-}<br>]<\/p>\n\n\n\n<p>Here\u2019s the breakdown:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Bisulfite Ion<\/strong>: The formula for bisulfite is (\\text{HSO}_3^-). It contains one proton (H\u207a) bound to the sulfite ion ((\\text{SO}_3^{2-})).<\/li>\n\n\n\n<li><strong>Conjugate Base<\/strong>: When (\\text{HSO}_3^-) loses a proton (H\u207a), the resulting species is the sulfite ion ((\\text{SO}_3^{2-})). This is the conjugate base of bisulfite.<\/li>\n<\/ol>\n\n\n\n<p>The key concept here is that the conjugate base is the particle that is left after an acid (such as (\\text{HSO}_3^-)) donates a proton. Since (\\text{HSO}_3^-) has a negative charge and contains a hydrogen atom, its conjugate base will have one less hydrogen, leading to the sulfite ion, which is also negatively charged, but has lost one proton.<\/p>\n\n\n\n<p>Thus, the <strong>conjugate base of (\\text{HSO}_3^-)<\/strong> is <strong>(\\text{SO}_3^{2-})<\/strong>.<\/p>\n\n\n\n<p>This principle is consistent with the Br\u00f8nsted-Lowry theory of acids and bases, which defines acids as proton donors and bases as proton acceptors. In this case, (\\text{HSO}_3^-) donates a proton to become (\\text{SO}_3^{2-}).<\/p>\n","protected":false},"excerpt":{"rendered":"<p>What is the conjugate base of hso3\u2212? express your answer as a chemical formula. The Correct Answer and Explanation is: The conjugate base of the bisulfite ion ((\\text{HSO}_3^-)) is the sulfite ion, (\\text{SO}_3^{2-}). Explanation: In acid-base chemistry, a conjugate base is the species that remains after an acid has donated a proton (H\u207a). In this [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-169629","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/169629","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=169629"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/169629\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=169629"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=169629"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=169629"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}