{"id":169863,"date":"2024-11-19T14:25:39","date_gmt":"2024-11-19T14:25:39","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=169863"},"modified":"2024-11-19T14:25:46","modified_gmt":"2024-11-19T14:25:46","slug":"how-does-the-hybridization-of-the-sulfur-atom-change-in-the-series-sf2-sf4-sf6","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2024\/11\/19\/how-does-the-hybridization-of-the-sulfur-atom-change-in-the-series-sf2-sf4-sf6\/","title":{"rendered":"How does the hybridization of the sulfur atom change in the series SF2, SF4, SF6"},"content":{"rendered":"\n<p>How does the hybridization of the sulfur atom change in the series SF2, SF4, SF6?<br>a. sp, sp\u00b3, sp\u00b3d\u00b2<br>b. sp\u00b3, sp\u00b3d, sp\u00b3d\u00b2<br>c.sp\u00b3, sp\u00b3d\u00b2, sp\u00b3d\u00b2<br>d. sp\u00b3, sp\u00b3, sp\u00b3d\u00b2<br>e. sp, sp\u00b3d, sp\u00b3d\u00b2<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>The correct answer is <strong>b. sp\u00b3, sp\u00b3d, sp\u00b3d\u00b2<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>The hybridization of a central atom depends on its bonding and the number of electron pairs (both bonding and lone pairs) around it. Let&#8217;s break it down for SF\u2082, SF\u2084, and SF\u2086.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>SF\u2082 (Sulfur Difluoride)<\/strong>:<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Sulfur in SF\u2082 has 2 bonding pairs (from the two fluorine atoms) and 2 lone pairs.<\/li>\n\n\n\n<li>The total number of regions of electron density around sulfur is 4 (2 bonding pairs + 2 lone pairs).<\/li>\n\n\n\n<li>To minimize repulsion, these four regions arrange in a <strong>tetrahedral<\/strong> geometry, which requires <strong>sp\u00b3 hybridization<\/strong>.<\/li>\n\n\n\n<li>Therefore, the sulfur atom in SF\u2082 is <strong>sp\u00b3 hybridized<\/strong>.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>SF\u2084 (Sulfur Tetrafluoride)<\/strong>:<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Sulfur in SF\u2084 has 4 bonding pairs (from the four fluorine atoms) and 1 lone pair.<\/li>\n\n\n\n<li>The total number of electron regions around sulfur is 5 (4 bonding pairs + 1 lone pair).<\/li>\n\n\n\n<li>A five-region electron configuration results in a <strong>trigonal bipyramidal<\/strong> geometry, which requires <strong>sp\u00b3d hybridization<\/strong>.<\/li>\n\n\n\n<li>Therefore, the sulfur atom in SF\u2084 is <strong>sp\u00b3d hybridized<\/strong>.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>SF\u2086 (Sulfur Hexafluoride)<\/strong>:<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Sulfur in SF\u2086 has 6 bonding pairs (from the six fluorine atoms) and no lone pairs.<\/li>\n\n\n\n<li>The total number of regions of electron density around sulfur is 6 (all bonding pairs).<\/li>\n\n\n\n<li>A six-region electron configuration leads to an <strong>octahedral<\/strong> geometry, which requires <strong>sp\u00b3d\u00b2 hybridization<\/strong>.<\/li>\n\n\n\n<li>Therefore, the sulfur atom in SF\u2086 is <strong>sp\u00b3d\u00b2 hybridized<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p>Thus, the hybridization sequence follows: <strong>sp\u00b3<\/strong> for SF\u2082, <strong>sp\u00b3d<\/strong> for SF\u2084, and <strong>sp\u00b3d\u00b2<\/strong> for SF\u2086.<\/p>\n\n\n\n<p>This pattern corresponds to option <strong>b<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>How does the hybridization of the sulfur atom change in the series SF2, SF4, SF6?a. sp, sp\u00b3, sp\u00b3d\u00b2b. sp\u00b3, sp\u00b3d, sp\u00b3d\u00b2c.sp\u00b3, sp\u00b3d\u00b2, sp\u00b3d\u00b2d. sp\u00b3, sp\u00b3, sp\u00b3d\u00b2e. sp, sp\u00b3d, sp\u00b3d\u00b2 The Correct Answer and Explanation is : The correct answer is b. sp\u00b3, sp\u00b3d, sp\u00b3d\u00b2. Explanation: The hybridization of a central atom depends on its bonding [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-169863","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/169863","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=169863"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/169863\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=169863"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=169863"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=169863"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}