CH3OH is soluble in H\u2082O. In C5H\u20812, this solute would be:
A) More soluble
B) Less soluble
C) Equally soluble<\/p>\n\n\n\n
The Correct Answer and Explanation is:<\/mark><\/strong><\/p>\n\n\n\n The correct answer is B) Less soluble<\/strong>.<\/p>\n\n\n\n The solubility of a solute in a solvent is largely governed by the principle “like dissolves like,” which means that polar solutes tend to dissolve in polar solvents, and nonpolar solutes tend to dissolve in nonpolar solvents. This principle relies on the interactions between the solute and solvent molecules.<\/p>\n\n\n\n Thus, C\u2085H\u2081\u2082 is less soluble in water<\/strong> compared to CH\u2083OH. Therefore, the correct answer is B) Less soluble<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":" CH3OH is soluble in H\u2082O. In C5H\u20812, this solute would be:A) More solubleB) Less solubleC) Equally soluble The Correct Answer and Explanation is: The correct answer is B) Less soluble. Explanation: The solubility of a solute in a solvent is largely governed by the principle “like dissolves like,” which means that polar solutes tend to […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-169908","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/169908","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=169908"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/169908\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=169908"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=169908"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=169908"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}Explanation:<\/h3>\n\n\n\n
\n
Methanol (CH\u2083OH) is a polar molecule. It has an -OH (hydroxyl) group, which is capable of forming hydrogen bonds with water molecules. Water (H\u2082O) is also highly polar and can form hydrogen bonds due to its own -OH groups. This allows CH\u2083OH to dissolve well in water because both substances can interact through strong hydrogen bonding.<\/li>\n\n\n\n
Cyclopentane (C\u2085H\u2081\u2082) is a nonpolar molecule. It consists of a hydrocarbon chain, which lacks the ability to form hydrogen bonds with water molecules. Water, being highly polar, does not interact well with nonpolar substances like cyclopentane. As a result, cyclopentane has very low solubility in water. The lack of polar interactions between cyclopentane and water leads to a weak solubility.<\/li>\n\n\n\n
When comparing the solubility of CH\u2083OH in water and C\u2085H\u2081\u2082 in water, it is clear that CH\u2083OH is much more soluble in water than C\u2085H\u2081\u2082. The polar nature of CH\u2083OH allows for favorable interactions with water molecules, leading to a higher solubility. On the other hand, C\u2085H\u2081\u2082, being nonpolar, does not interact well with polar water molecules, making it significantly less soluble.<\/li>\n<\/ol>\n\n\n\n