Write the formulas for the following compounds: (a) copper(l) cyanide, (b) strontium chlorite, (c) perbromic acid,(d) hydroiodic acid, (e) disodium ammonium phosphate, (f) potassium dihydrogen phosphate, (g) iodine heptafluoride, (h) tetraphosphorus decasulfide, (i) mercury(ll) oxide, (j) mercury(l) iodide, (k) selenium hexafluoride.<\/p>\n\n\n\n
The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n Here are the chemical formulas for the compounds you’ve listed, along with a brief explanation of how each formula is derived:<\/p>\n\n\n\n Understanding oxidation states and charge balance is essential when deriving these formulas.<\/p>\n","protected":false},"excerpt":{"rendered":" Write the formulas for the following compounds: (a) copper(l) cyanide, (b) strontium chlorite, (c) perbromic acid,(d) hydroiodic acid, (e) disodium ammonium phosphate, (f) potassium dihydrogen phosphate, (g) iodine heptafluoride, (h) tetraphosphorus decasulfide, (i) mercury(ll) oxide, (j) mercury(l) iodide, (k) selenium hexafluoride. The Correct Answer and Explanation is : Here are the chemical formulas for the […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-170270","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/170270","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=170270"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/170270\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=170270"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=170270"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=170270"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}\n
Formula<\/strong>: ( \\text{CuCN} )
Copper(I) has a +1 charge, and the cyanide ion (CN(^-)) has a -1 charge. To balance the charges, one copper ion combines with one cyanide ion to form copper(I) cyanide.<\/li>\n\n\n\n
Formula<\/strong>: ( \\text{Sr(ClO}_2\\text{)}_2 )
Strontium (Sr) has a +2 charge, while chlorite (ClO(_2)^-) has a -1 charge. To balance the charges, two chlorite ions are needed for each strontium ion, resulting in ( \\text{Sr(ClO}_2\\text{)}_2 ).<\/li>\n\n\n\n
Formula<\/strong>: ( \\text{HBrO}_4 )
Perbromic acid contains the perbromate ion (BrO(_4)^-) with a -1 charge. The hydrogen ion (H(^+)) balances this charge, so the formula is ( \\text{HBrO}_4 ).<\/li>\n\n\n\n
Formula<\/strong>: ( \\text{HI} )
Hydroiodic acid consists of hydrogen (H(^+)) and iodide (I(^-)). The charges balance in a 1:1 ratio, so the formula is ( \\text{HI} ).<\/li>\n\n\n\n
Formula<\/strong>: ( \\text{Na}_2\\text{NH}_4\\text{PO}_4 )
The ammonium ion (NH(_4)^+) is paired with phosphate (PO(_4)^{3-}). To balance charges, two sodium ions (Na(^+)) are needed for each ammonium ion, giving the formula ( \\text{Na}_2\\text{NH}_4\\text{PO}_4 ).<\/li>\n\n\n\n
Formula<\/strong>: ( \\text{KH}_2\\text{PO}_4 )
Potassium (K(^+)) combines with the dihydrogen phosphate ion (H(_2)PO(_4)^-) to form the neutral compound ( \\text{KH}_2\\text{PO}_4 ).<\/li>\n\n\n\n
Formula<\/strong>: ( \\text{IF}_7 )
Iodine forms a +7 oxidation state in iodine heptafluoride, while fluoride (F(^-)) has a -1 charge. Seven fluoride ions balance the iodine ion, so the formula is ( \\text{IF}_7 ).<\/li>\n\n\n\n
Formula<\/strong>: ( \\text{P}4\\text{S}<\/em>{10} )
This compound consists of four phosphorus atoms and ten sulfur atoms, so its formula is ( \\text{P}4\\text{S}<\/em>{10} ).<\/li>\n\n\n\n
Formula<\/strong>: ( \\text{HgO} )
Mercury(II) has a +2 charge, and oxygen has a -2 charge. The charges balance in a 1:1 ratio, so the formula is ( \\text{HgO} ).<\/li>\n\n\n\n
Formula<\/strong>: ( \\text{Hg}_2\\text{I}_2 )
Mercury(I) exists as a diatomic ion, ( \\text{Hg}_2^{2+} ). Iodide has a -1 charge, so two iodide ions are needed to balance the mercury(I) cation, resulting in ( \\text{Hg}_2\\text{I}_2 ).<\/li>\n\n\n\n
Formula<\/strong>: ( \\text{SeF}_6 )
Selenium hexafluoride consists of one selenium atom and six fluoride ions. The formula is ( \\text{SeF}_6 ), where the selenium atom is in the +6 oxidation state.<\/li>\n<\/ol>\n\n\n\nSummary of Charges and Formula Construction:<\/h3>\n\n\n\n
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