Write the complete balanced equation for the following reaction: c7h14 o2 yields co2 h2o<\/p>\n\n\n\n
The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n To balance the combustion reaction of heptanol (C\u2087H\u2081\u2084O\u2082), the general formula for a combustion reaction is:<\/p>\n\n\n\n [ In this case, the fuel is heptanol (C\u2087H\u2081\u2084O\u2082). The complete balanced equation for the combustion of heptanol is:<\/p>\n\n\n\n [ Thus, the balanced combustion equation for heptanol is:<\/p>\n\n\n\n [ This equation satisfies the law of conservation of mass, where the number of atoms of each element is the same on both sides of the reaction.<\/p>\n","protected":false},"excerpt":{"rendered":" Write the complete balanced equation for the following reaction: c7h14 o2 yields co2 h2o The Correct Answer and Explanation is : To balance the combustion reaction of heptanol (C\u2087H\u2081\u2084O\u2082), the general formula for a combustion reaction is: [\\text{Fuel} + O_2 \\rightarrow CO_2 + H_2O] In this case, the fuel is heptanol (C\u2087H\u2081\u2084O\u2082). The complete balanced […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-170321","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/170321","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=170321"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/170321\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=170321"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=170321"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=170321"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
\\text{Fuel} + O_2 \\rightarrow CO_2 + H_2O
]<\/p>\n\n\n\n
\\text{C}7\\text{H}<\/em>{14}\\text{O}_2 + 11\\text{O}_2 \\rightarrow 7\\text{CO}_2 + 7\\text{H}_2\\text{O}
]<\/p>\n\n\n\nExplanation:<\/h3>\n\n\n\n
\n
The unbalanced combustion equation for heptanol is:
[
\\text{C}7\\text{H}<\/em>{14}\\text{O}_2 + O_2 \\rightarrow CO_2 + H_2O
]
Heptanol (C\u2087H\u2081\u2084O\u2082) reacts with oxygen (O\u2082) to produce carbon dioxide (CO\u2082) and water (H\u2082O).<\/li>\n\n\n\n
The carbon in heptanol (C\u2087) must balance with the carbon dioxide (CO\u2082). Therefore, you need 7 CO\u2082 molecules:
[
\\text{C}7\\text{H}<\/em>{14}\\text{O}_2 + O_2 \\rightarrow 7\\text{CO}_2 + H_2O
]<\/li>\n\n\n\n
There are 14 hydrogen atoms in heptanol (C\u2087H\u2081\u2084O\u2082), so you need 7 H\u2082O molecules to balance the hydrogen atoms:
[
\\text{C}7\\text{H}<\/em>{14}\\text{O}_2 + O_2 \\rightarrow 7\\text{CO}_2 + 7\\text{H}_2\\text{O}
]<\/li>\n\n\n\n
On the right-hand side of the equation, you have 7 CO\u2082 molecules (7 \u00d7 2 = 14 oxygen atoms) and 7 H\u2082O molecules (7 \u00d7 1 = 7 oxygen atoms), for a total of 21 oxygen atoms. On the left, heptanol (C\u2087H\u2081\u2084O\u2082) already provides 2 oxygen atoms, so you need 19 more from oxygen molecules (O\u2082). Since each O\u2082 molecule provides 2 oxygen atoms, you need 11 O\u2082 molecules:
[
\\text{C}7\\text{H}<\/em>{14}\\text{O}_2 + 11\\text{O}_2 \\rightarrow 7\\text{CO}_2 + 7\\text{H}_2\\text{O}
]<\/li>\n<\/ol>\n\n\n\n
\\text{C}7\\text{H}<\/em>{14}\\text{O}_2 + 11\\text{O}_2 \\rightarrow 7\\text{CO}_2 + 7\\text{H}_2\\text{O}
]<\/p>\n\n\n\n